{"id":82372,"date":"2017-08-22T20:33:38","date_gmt":"2017-08-22T23:33:38","guid":{"rendered":"http:\/\/clubes.obmep.org.br\/blog\/?page_id=82372"},"modified":"2024-11-26T23:23:47","modified_gmt":"2024-11-27T02:23:47","slug":"brincando-com-geometria-setor-e-segmento-circular","status":"publish","type":"page","link":"https:\/\/clubes.obmep.org.br\/blog\/brincando-com-geometria-setor-e-segmento-circular\/","title":{"rendered":".Sala de Estudo: Setor e segmento circular"},"content":{"rendered":"<hr style=\"height:1px;background-color:#8B5A2B; border: 0 none\"\/>\n<hr style=\"height:1px;background-color:#8B5A2B; border: 0 none\"\/>\n<p class=\"tis cm\"  style=\"margin:10px;line-height:30px; font-size:35px;\">Setor circular e segmento circular<\/p>\n<hr style=\"height:1px;background-color:#8B5A2B; border: 0 none\"\/>\n<hr style=\"height:1px;background-color:#8B5A2B; border: 0 none\"\/>\n<p style=\"margin:30px \">\n<div style=\"margin:10px; float:right;\">\n<table style=\"border:0px;  height:auto; margin-left: auto; margin-right: auto;width:640px;\">\n<tr>\n<td class=\"bf\"><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-1001 alignright\" style=\"border: 0px;\" alt=\"\" src=\"http:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2013\/01\/menino.jpg\" width=\"80\" height=\"95\" \/><\/td>\n<td class=\"bf\">\n<p class=\"fala bgm3 cbm3\" style=\"width:520px; line-height: 20px; font-size:14px\" > Vamos discutir sobre duas regi\u00f5es de um c\u00edrculo que, embora sejam bastante utilizadas na solu\u00e7\u00e3o de problemas envolvendo \u00e1reas, \u00e9 comum certa confus\u00e3o entre elas. Ambas as regi\u00f5es dependem de uma circunfer\u00eancia e de um \u00e2ngulo central (ou um arco de circunfer\u00eancia), elas t\u00eam uma rela\u00e7\u00e3o entre si, mas s\u00e3o objetos matem\u00e1ticos distintos.<br \/>\n<span style=\"color: #8B5A2B;padding-left:90px;letter-spacing:4px;text-align:center\"><strong>Bom proveito!<\/strong><\/span><\/p>\n<\/td>\n<\/tr>\n<\/table>\n<\/div>\n<div style=\"clear: both;\"><\/div>\n<p style=\"margin:30px\">\n<div class=\"gr1 cbm2\" >\n<p class=\"ti2 cm\"  style=\"margin:10px;line-height:26px; font-size:24px;\">Setor Circular <\/p>\n<hr style=\"height:1px;background-color:#8B5A2B; border: 0 none\"\/>\n<p style=\"margin:30px\">\n<div class=\"gree cbm6 bgm2\" style=\"width:95%;\">\nConsidere um c\u00edrculo [tex]c[\/tex] de centro [tex]O[\/tex] e fixe dois pontos [tex]A[\/tex] e [tex]B[\/tex] da circunfer\u00eancia de [tex]c[\/tex].<br \/>\nChamamos <span class=\"cm\"><strong> setor circular<\/strong><\/span> a regi\u00e3o do c\u00edrculo [tex]c[\/tex] limitada pelo arco da circunfer\u00eancia definido por [tex]A[\/tex] e [tex]B[\/tex] e pelos raios [tex]OA[\/tex] e [tex]OB[\/tex].<br \/>\nSe [tex]A[\/tex] e [tex]B[\/tex] n\u00e3o forem extremidades de um di\u00e2metro, o setor circular definido pode receber nomes particulares:  o setor \u00e9 chamado de <strong>setor circular menor<\/strong>, se o arco que o define for o chamado &#8220;arco menor&#8221;; caso contr\u00e1rio, o setor \u00e9 dito <strong>setor circular maior<\/strong>.<\/div>\n<p style=\"font-size:11px; margin: 20px 50px 10px 50px\">\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2017\/09\/fig10.png\" style=\"border:none;\" alt=\"\" width=\"800\" height=\"240\" class=\"aligncenter size-full wp-image-90093\" srcset=\"https:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2017\/09\/fig10.png 900w, https:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2017\/09\/fig10-300x90.png 300w, https:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2017\/09\/fig10-768x231.png 768w\" sizes=\"auto, (max-width: 800px) 100vw, 800px\" \/> <\/p>\n<p>De modo geral, o arco utilizado na defini\u00e7\u00e3o de um setor circular \u00e9 o dito &#8220;arco menor&#8221;; assim, quase todas as nossas figuras mostram setores circulares definidos por arcos menores, mas as conclus\u00f5es aqui estabelecidas s\u00e3o v\u00e1lidas para setores circulares definidos por arcos quaisquer. Observe que, em um mesmo c\u00edrculo, a soma das \u00e1reas do setor circular maior e do setor circular menor definidos pelos pontos [tex]A[\/tex] e [tex]B[\/tex] \u00e9 exatamente a \u00e1rea do pr\u00f3prio c\u00edrculo.<\/p>\n<table class=\"gr1\">\n<tr class=\"bf\">\n<td class=\"bf gr1\" style=\"width:45%; vertical-align:top;\">Perceba que os raios [tex]OA[\/tex] e [tex]OB[\/tex] e o centro [tex]O[\/tex] definem um \u00e2ngulo central e um arco.<br \/>\nAssim, podemos associar a cada setor circular tr\u00eas medidas: <strong>o comprimento [tex]R[\/tex] do raio do c\u00edrculo, a medida  [tex]\\alpha[\/tex] do \u00e2ngulo central<\/strong> e <strong>o comprimento [tex]l [\/tex] do arco<\/strong>.<br \/>\nSendo uma regi\u00e3o do plano, o setor circular tem uma \u00e1rea que pode ser calculada se conhecemos a medida [tex]R[\/tex]  e a medida  [tex]\\alpha[\/tex] (em radianos ou em graus).<br \/>\nSe conhecermos o comprimento do arco definido pelos pontos [tex]A[\/tex] e [tex]B[\/tex], al\u00e9m do comprimento [tex]R[\/tex] do raio, tamb\u00e9m \u00e9 poss\u00edvel obtermos a \u00e1rea do setor circular.<\/td>\n<td class=\"bf\" style=\"text-align:right;\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2017\/07\/fig04.png\"  style=\"border:none;\" alt=\"\" width=\"207\" height=\"209\" class=\"alignright  size-full wp-image-79884\" \/><\/td>\n<td class=\"bf\" style=\"text-align:right;\">\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2017\/07\/setor2.png\" style=\"border:none;\" alt=\"\" width=\"200\" height=\"201\" class=\"alignright size-full wp-image-80201\" srcset=\"https:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2017\/07\/setor2.png 200w, https:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2017\/07\/setor2-150x150.png 150w\" sizes=\"auto, (max-width: 200px) 100vw, 200px\" \/><\/p>\n<\/td>\n<\/tr>\n<\/table>\n<p><span class=\"cm\" style=\"font-size: 25px;padding-left:30px;\"><strong> &#10000;<\/strong> <\/span> <strong>\u00c1rea de um setor circular de raio [tex]R[\/tex] e [tex]\\alpha[\/tex] radianos<\/strong><br \/>\n[tex]\\qquad \\qquad\\boxed{A_{setor}=\\dfrac{\\alpha R^{ \\, 2}}{2}}[\/tex]<\/p>\n<p style=\"margin:30px\">\n<p><span class=\"cm\" style=\"font-size: 25px;padding-left:30px;\"> <strong>&#10000;<\/strong> <\/span> <strong>\u00c1rea de um setor circular de raio [tex]R[\/tex] e [tex]\\alpha[\/tex] graus<\/strong><br \/>\n[tex]\\qquad \\qquad \\boxed{A_{setor}=\\dfrac{\\pi R^{ \\, 2} \\alpha}{360}}[\/tex]<\/p>\n<p style=\"margin:30px\">\n<p><span class=\"cm\" style=\"font-size: 25px;padding-left:30px;\"><strong> &#10000;<\/strong> <\/span> <strong>\u00c1rea de um setor circular de raio [tex]R[\/tex] e comprimento de arco [tex]l[\/tex]<\/strong><br \/>\n[tex]\\qquad \\qquad\\boxed{A_{setor}=\\dfrac{l\\cdot R}{2}}[\/tex]<\/p>\n<p style=\"margin:30px\">\n<hr style=\"height:4px; width:100%;background-color:#8B5A2B; border: 0 none\"\/>\n<p class=\"ti3\" style=\"margin:30px;\">Para saber de onde vieram essas tr\u00eas f\u00f3rmulas, clique no bot\u00e3o abaixo.<\/p>\n<div style=\"text-align:center;\">\n<input class=\"bo1 cm  bgm2 cbm8\" value=\"F\u00f3rmulas\" title=\"Clique aqui\" type=\"button\" onclick=    \"if(this.parentNode.getElementsByTagName('div')[0].style.display != ''){this.parentNode.getElementsByTagName('div')[0].style.display = '';this.value = 'Ocultar';} else{this.parentNode.getElementsByTagName('div')[0].style.display = 'none'; this.value = 'F\u00f3rmulas';}\" \/>    <\/p>\n<div class=\"gree cbm4\" style=\"display: none;\">\n<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2017\/07\/setor.png\" style=\"border:none;\" alt=\"\" width=\"205\" height=\"206\" class=\"alignright size-full wp-image-80192\" srcset=\"https:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2017\/07\/setor.png 205w, https:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2017\/07\/setor-150x150.png 150w\" sizes=\"auto, (max-width: 205px) 100vw, 205px\" \/><\/p>\n<p>O setor circular \u00e9 uma parte do c\u00edrculo que o define e sua \u00e1rea depende diretamente da medida do \u00e2ngulo central ou do comprimento de arco a ele associado. Podemos, ent\u00e3o, calcular a \u00e1rea de um setor circular aplicando uma regra de tr\u00eas simples j\u00e1 que esta \u00e1rea ser\u00e1 uma porcentagem da \u00e1rea do c\u00edrculo que o define: [tex]\\pi R^2 [\/tex]<\/p>\n<p style=\"margin:10px\">\n<p><span class=\"cm\" style=\"font-size: 25px;\"> <strong>&#10000;<\/strong> <\/span> <strong>\u00c1rea de um setor circular de raio [tex]R[\/tex] e [tex]\\alpha[\/tex] radianos<\/strong><br \/>\nA regra de tr\u00eas simples<\/p>\n<table class=\"bgm1\" style=\"border: 1px solid #CDBA96; width:40%; height:auto;text-align:center;  margin-left: auto; margin-right:auto;\">\n<tr>\n<td class=\"bgm1\" style=\"border: 1px solid #CDBA96; \"> [tex]2\\pi \\, rad[\/tex] <\/td>\n<td class=\"bgm1\" style=\"border: 1px solid #CDBA96\"> &#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8211;<\/td>\n<td class=\"bgm1\"  style=\"border: 1px solid #CDBA96\"> [tex]\\pi R^2[\/tex] <\/td>\n<\/tr>\n<tr>\n<td class=\"bgm1\" style=\"border: 1px solid #CDBA96\"> [tex]\\alpha \\, rad [\/tex]<\/td>\n<td class=\"bgm1\" style=\"border: 1px solid #CDBA96\"> &#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8211;<\/td>\n<td class=\"bgm1\" style=\"border: 1px solid #CDBA96\"> [tex]A_{setor}[\/tex] <\/td>\n<\/tr>\n<\/table>\n<p>garante que [tex]\\boxed{A_{setor}=\\dfrac{\\alpha R^{ \\, 2}}{2}}[\/tex]<\/p>\n<p style=\"margin:20px\">\n<p><span class=\"cm\" style=\"font-size: 25px;\"> <strong>&#10000;<\/strong> <\/span> <strong>\u00c1rea de um setor circular de raio [tex]R[\/tex] e [tex]\\alpha[\/tex] graus<\/strong><br \/>\nA regra de tr\u00eas simples<\/p>\n<table class=\"bgm1\" style=\"border: 1px solid #CDBA96; width:40%; height:auto;text-align:center;  margin-left: auto; margin-right:auto;\">\n<tr>\n<td class=\"bgm1\" style=\"border: 1px solid #CDBA96; \"> [tex]360^{\\circ}[\/tex] <\/td>\n<td class=\"bgm1\" style=\"border: 1px solid #CDBA96\"> &#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8211;<\/td>\n<td class=\"bgm1\"  style=\"border: 1px solid #CDBA96\"> [tex]\\pi R^2[\/tex] <\/td>\n<\/tr>\n<tr>\n<td class=\"bgm1\" style=\"border: 1px solid #CDBA96\"> [tex]\\alpha^{\\circ} [\/tex]<\/td>\n<td class=\"bgm1\" style=\"border: 1px solid #CDBA96\"> &#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8211;<\/td>\n<td class=\"bgm1\" style=\"border: 1px solid #CDBA96\"> [tex]A_{setor}[\/tex] <\/td>\n<\/tr>\n<\/table>\n<p>garante agora que [tex]\\boxed{A_{setor}=\\dfrac{\\pi R^{ \\, 2} \\alpha}{360}}[\/tex]<\/p>\n<p style=\"margin:20px\">\n<p><span class=\"cm\" style=\"font-size: 25px;\"> <strong>&#10000;<\/strong> <\/span> <strong>\u00c1rea de um setor circular de raio [tex]R[\/tex] e comprimento de arco [tex]l[\/tex]<\/strong><br \/>\nMais uma regra de tr\u00eas simples:<\/p>\n<table class=\"bgm1\" style=\"border: 1px solid #CDBA96; width:40%; height:auto;text-align:center;  margin-left: auto; margin-right:auto;\">\n<tr>\n<td class=\"bgm1\" style=\"border: 1px solid #CDBA96; \"> [tex]2\\pi R[\/tex] <\/td>\n<td class=\"bgm1\" style=\"border: 1px solid #CDBA96\"> &#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8211;<\/td>\n<td class=\"bgm1\"  style=\"border: 1px solid #CDBA96\"> [tex]\\pi R^2[\/tex] <\/td>\n<\/tr>\n<tr>\n<td class=\"bgm1\" style=\"border: 1px solid #CDBA96\"> [tex]l [\/tex]<\/td>\n<td class=\"bgm1\" style=\"border: 1px solid #CDBA96\"> &#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8211;<\/td>\n<td class=\"bgm1\" style=\"border: 1px solid #CDBA96\"> [tex]A_{setor}[\/tex] <\/td>\n<\/tr>\n<\/table>\n<p>Temos, agora, que [tex]\\boxed{A_{setor}=\\dfrac{l\\cdot R}{2}}[\/tex]<\/p>\n<p style=\"margin:20px\">\n<\/div>\n<\/div>\n<p style=\"margin:30px\">\n<hr style=\"height:4px; width:100%;background-color:#8B5A2B; border: 0 none\"\/>\n<p class=\"ti3\" style=\"margin:30px;\">Achou a \u00faltima f\u00f3rmula parecida com a da \u00e1rea de um tri\u00e2ngulo?<br \/>\nEnt\u00e3o, clique no bot\u00e3o abaixo.<\/p>\n<div style=\"text-align:center;\">\n<input class=\"bo1 cm bgm2  cbm8\" value=\"Ilustra\u00e7\u00e3o\" title=\"Clique aqui\" type=\"button\" onclick=    \"if(this.parentNode.getElementsByTagName('div')[0].style.display != ''){this.parentNode.getElementsByTagName('div')[0].style.display = '';this.value = 'Ocultar';} else{this.parentNode.getElementsByTagName('div')[0].style.display = 'none'; this.value = 'Ilustra\u00e7\u00e3o';}\" \/>    <\/p>\n<div class=\"gree cbm3\" style=\"display: none;width:550px;\">\n<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2017\/07\/setor4.png\" style=\"border:none;\"  alt=\"\" width=\"594\" height=\"370\" class=\"aligncenter size-full wp-image-80419\" srcset=\"https:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2017\/07\/setor4.png 594w, https:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2017\/07\/setor4-300x187.png 300w\" sizes=\"auto, (max-width: 594px) 100vw, 594px\" \/>\n<\/div>\n<\/div>\n<\/div>\n<p style=\"margin:30px\">\n<hr style=\"height:1px; width:20%;background-color:#8B5A2B; margin-top: 8px; margin-bottom: 8px;border: 0 none\"\/>\n<hr style=\"height:2px; width:40%;background-color:#8B5A2B;margin-top: 8px; margin-bottom: 8px; border: 0 none\"\/>\n<hr style=\"height:3px; width:50%;background-color:#8B5A2B; margin-top: 8px; margin-bottom: 8px;border: 0 none\"\/>\n<hr style=\"height:3px; width:50%;background-color:#8B5A2B; margin-top: 8px; margin-bottom: 8px;border: 0 none\"\/>\n<hr style=\"height:2px; width:40%;background-color:#8B5A2B; margin-top: 8px; margin-bottom: 8px;border: 0 none\"\/>\n<hr style=\"height:1px; width:20%;background-color:#8B5A2B;margin-top: 8px; margin-bottom: 8px; border: 0 none\"\/>\n<p style=\"margin:30px\">\n<div class=\"gr1 cbm2\">\n<p class=\"ti2 cm\"  style=\"margin:10px;line-height:26px; font-size:24px;\">Segmento Circular <\/p>\n<hr style=\"height:1px;background-color:#8B5A2B; border: 0 none\"\/>\n<p style=\"margin:30px\">\n<div class=\"gree cbm6 bgm2\" style=\"width:95%;\">\nConsidere um c\u00edrculo [tex]c[\/tex] de centro [tex]O[\/tex] e fixe dois pontos [tex]A[\/tex] e [tex]B[\/tex] da circunfer\u00eancia de [tex]c[\/tex].<br \/>\nChamamos <span class=\"cm\"><strong> segmento circular<\/strong><\/span> a regi\u00e3o do c\u00edrculo [tex]c[\/tex] limitada pela corda e pelo arco da circunfer\u00eancia definidos por [tex]A[\/tex] e [tex]B[\/tex].<br \/>\nSe [tex]A[\/tex] e [tex]B[\/tex] n\u00e3o forem extremidades de um di\u00e2metro, o segmento circular definido tamb\u00e9m pode receber nomes particulares: se o arco que define o segmento circular for o chamado &#8220;arco menor&#8221;, ent\u00e3o temos o <strong>segmento circular menor<\/strong>, caso contr\u00e1rio, temos um <strong>segmento circular maior<\/strong>.<\/div>\n<p style=\"font-size:11px; margin: 20px 50px 10px 50px\">\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2017\/09\/fig11.png\" style=\"border:none; alt=\"\" width=\"800\" height=\"227\" class=\"aligncenter size-full wp-image-90099\" srcset=\"https:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2017\/09\/fig11.png 942w, https:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2017\/09\/fig11-300x85.png 300w, https:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2017\/09\/fig11-768x218.png 768w\" sizes=\"auto, (max-width: 800px) 100vw, 800px\" \/><\/p>\n<p>De modo geral, o arco utilizado na defini\u00e7\u00e3o de um segmento circular \u00e9 tamb\u00e9m o &#8220;arco menor&#8221;; assim, quase todas as nossas figuras mostram setores circulares definidos por arcos menores.  Observe que, em um mesmo c\u00edrculo, a soma das \u00e1reas do segmento circular maior e do segmento circular menor definidos pelos pontos [tex]A[\/tex] e [tex]B[\/tex] \u00e9 igual \u00e0 \u00e1rea do pr\u00f3prio c\u00edrculo.\n <\/p>\n<table class=\"gr1\">\n<tr class=\"bf\">\n<td class=\"bf gr1\" style=\"width:45%; vertical-align:top;\">Perceba que os  pontos [tex]O[\/tex], [tex]A[\/tex] e [tex]B[\/tex] definem os raios [tex]OA[\/tex] e [tex]OB[\/tex] e um \u00e2ngulo central.<br \/>\nAssim, podemos associar a cada segmento circular duas medidas: <strong>o comprimento [tex]R[\/tex] do raio do c\u00edrculo e a medida  [tex]\\alpha[\/tex] do \u00e2ngulo central<\/strong>.<br \/>\nSendo tamb\u00e9m uma regi\u00e3o do plano, o segmento circular tem uma \u00e1rea que pode ser calculada se conhecemos a medida [tex]R[\/tex]  e a medida  [tex]\\alpha[\/tex] em radianos.<\/td>\n<td class=\"bf\" style=\"text-align:right;\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2017\/07\/fig05.png\" style=\"border:none;\" alt=\"\" width=\"207\"  height=\"209\" class=\"alignright size-full wp-image-78544\" \/>\n<\/td>\n<td class=\"bf\" style=\"text-align:right;\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2017\/07\/fig06.png\" style=\"border:none;\"alt=\"\" width=\"207\" height=\"209\" class=\"alignright  size-full wp-image-80021\" \/><\/p>\n<\/td>\n<\/tr>\n<\/table>\n<p><span class=\"cm\" style=\"font-size: 25px;padding-left:30px;\"><strong> &#10000;<\/strong> <\/span> <strong>\u00c1rea de um segmento circular de raio [tex]R[\/tex] e [tex]\\alpha[\/tex] radianos<\/strong><br \/>\n[tex]\\qquad \\qquad \\boxed{A_{segm}=\\dfrac{R^{ \\, 2}}{2}\\left(\\alpha-sen \\, \\alpha\\right)}[\/tex]<\/p>\n<p style=\"margin:30px\">\n<hr style=\"height:4px; width:100%;background-color:#8B5A2B; border: 0 none\"\/>\n<p class=\"ti3\" style=\"margin:30px;\">Para saber de onde veio essa f\u00f3rmula, clique no bot\u00e3o abaixo.<\/p>\n<div style=\"text-align:center;\">\n<input class=\"bo1 cm bgm2  cbm8\" value=\"F\u00f3rmula\" title=\"Clique aqui\" type=\"button\" onclick=    \"if(this.parentNode.getElementsByTagName('div')[0].style.display != ''){this.parentNode.getElementsByTagName('div')[0].style.display = '';this.value = 'Ocultar';} else{this.parentNode.getElementsByTagName('div')[0].style.display = 'none'; this.value = 'F\u00f3rmula';}\" \/>    <\/p>\n<div class=\"gree cbm4 \" style=\"display: none;\">\n<strong>Vejamos como obter a \u00e1rea do segmento circular.<\/strong><br \/>\nObserve que a \u00e1rea do segmento circular \u00e9 dada pela diferen\u00e7a entre a \u00e1rea do setor circular e a \u00e1rea do tri\u00e2ngulo [tex] OBC[\/tex]. <\/p>\n<p style=\"margin:10px \">\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2017\/07\/fig047.png\" style=\"border:none;\" alt=\"\" width=\"685\" height=\"200\" class=\"aligncenter size-full wp-image-78731\" srcset=\"https:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2017\/07\/fig047.png 685w, https:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2017\/07\/fig047-300x88.png 300w\" sizes=\"auto, (max-width: 685px) 100vw, 685px\" \/><\/p>\n<p style=\"margin:10px \">\n<p>Assim,  [tex]\\acute{A}rea=A_1-A_2[\/tex], onde <\/li>\n<ul>\n<li>[tex]\\acute{A}rea[\/tex]: \u00e1rea do segmento circular;<\/li>\n<li>[tex] A_1[\/tex]: \u00e1rea do setor circular;<\/li>\n<li>[tex] A_2[\/tex]: \u00e1rea do tri\u00e2ngulo [tex] OBC[\/tex].<\/li>\n<\/ul>\n<p>J\u00e1 sabemos que [tex]A_1=\\dfrac{\\alpha R^2}{2}[\/tex]; assim, basta encontrarmos [tex]A_2[\/tex]. Ent\u00e3o, vamos l\u00e1!<br \/>\nNote que [tex]A_2[\/tex] \u00e9 a \u00e1rea de um tri\u00e2ngulo, ent\u00e3o [tex]A_2=\\dfrac{base \\times altura}{2}[\/tex].<br \/>\nObserve a pr\u00f3xima figura e siga a dedu\u00e7\u00e3o.<\/p>\n<table class=\"gree\" style=\"border: 1px solid #ffffff; height:auto;\">\n<tr class=\"bf\">\n<td class=\"gree\"  style=\"border: 1px solid #ffffff; width:30% \">\n<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2017\/07\/fig048.png\" style=\"border:none\" alt=\"\" width=\"185\" height=\"209\" class=\"aligncenter size-full wp-image-78740\" \/>\n<\/td>\n<td class=\"gree\" style=\"border: 1px solid #ffffff; line-height:35px;\">\nComo [tex]A_2=\\dfrac{R \\times h}{2} [\/tex], precisamos obter uma express\u00e3o para [tex]h[\/tex] em termos dos dados conhecidos: [tex]R[\/tex] e [tex]\\alpha[\/tex].<br \/>\nComo o tri\u00e2ngulo [tex]ODB[\/tex] \u00e9 ret\u00e2ngulo, ent\u00e3o [tex]sen(\\pi-\\alpha)=\\dfrac{h}{R} \\, [\/tex] e, assim,<br \/>\n[tex]\\quad \\boxed{h= R \\, sen(\\pi-\\alpha)}[\/tex].<br \/>\nMas [tex]\\alpha[\/tex] e [tex]\\pi -\\alpha[\/tex] s\u00e3o medidas de \u00e2ngulos suplementares, logo<br \/>\n[tex]\\quad  sen \\, \\alpha=sen \\, (\\pi -\\alpha)[\/tex].<\/td>\n<\/tr>\n<\/table>\n<table class=\"gr1\">\n<tr>\n<td class=\"bf gree\" style=\"width:35%; vertical-align:top;\">\nDessa forma, [tex]h= R  \\,  sen \\, \\alpha[\/tex] e,<br \/>\nportanto:<\/p>\n<p style=\"margin:10px \">\n<p>[tex]\\quad A_2  =\\dfrac{R \\times h}{2}[\/tex]<\/p>\n<p style=\"margin:10px \">\n<p>[tex]\\quad A_2  =\\dfrac{R \\times R sen \\, \\alpha}{2}[\/tex]<\/p>\n<p style=\"margin:10px \">\n<p>[tex]\\quad A_2  =\\dfrac{R^2 sen \\, \\alpha}{2}[\/tex]<\/td>\n<td class=\"gree\" style=\"width:65%; vertical-align:top; border: 2px dashed #8B5A2B;\">\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2017\/07\/fig07.png\" alt=\"\" width=\"200\" height=\"202\" class=\"alignright size-full wp-image-80037\" \/><\/p>\n<p>Observe que se o \u00e2ngulo [tex]\\alpha[\/tex] fosse agudo, a altura  [tex]h= R  \\,  sen \\, \\alpha[\/tex] do tri\u00e2ngulo  [tex]ABO[\/tex] seria mais facilmente obtida; observe:<\/p>\n<p style=\"margin:10px \">\n<p>[tex]\\quad sen \\, \\alpha =\\dfrac{\\text{cateto oposto}}{\\text{hipotenusa}}[\/tex]<\/p>\n<p style=\"margin:10px \">\n<p>[tex]\\quad sen \\, \\alpha= \\dfrac{h}{R} [\/tex]<\/p>\n<p style=\"margin:10px \">\n<p>[tex]\\quad  h= R  \\,  sen \\, \\alpha[\/tex]\n<\/td>\n<\/tr>\n<\/table>\n<p>Pronto, finalmente podemos calcular a \u00e1rea do segmento circular:<br \/>\n[tex]\\quad \\acute{A}rea \\,  \\, = A_1-A_2 [\/tex]<\/p>\n<p style=\"margin:10px \">\n<p>[tex]\\qquad \\qquad =\\dfrac{\\alpha R^{ \\, 2}}{2}-\\dfrac{R^{ \\, 2} sen \\, \\alpha}{2}[\/tex]<\/p>\n<p style=\"margin:10px \">\n<p>[tex]\\qquad \\qquad =\\dfrac{R^{ \\, 2}}{2}\\left(\\alpha- sen \\, \\alpha\\right).[\/tex]<\/p>\n<p style=\"margin:20px \">\n<p>Portanto, [tex]\\boxed{{A_{segm}=\\dfrac{R^{ \\, 2}}{2}\\left(\\alpha-sen \\, \\alpha\\right)}}[\/tex]<\/p>\n<p style=\"margin:20px\">\n<\/div>\n<\/div>\n<p style=\"margin:20px \">\n<\/div>\n<p style=\"font-size: 16px;line-height: 30px;text-align: right; color: #8B5A2B;\">Novembro de 2017.<\/p>\n<p style=\"margin:10px\">\n<table style=\" height:auto; margin-left: auto; margin-right:auto;\">\n<tr>\n<td class=\"bf\"><img loading=\"lazy\" decoding=\"async\" class=\" wp-image-1001 alignright\" style=\"border: 0px;\" alt=\"explicador_p\" src=\"http:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2013\/01\/menino.jpg\" width=\"90\" height=\"108\" \/><\/td>\n<td class=\"bf\">\n<p class=\"fala bgm3 cbm3\" style=\"width:520px; line-height: 20px; font-size:14px\" > Esperamos que voc\u00ea tire proveito da explana\u00e7\u00e3o feita aqui.<br \/>\nNosso objetivo \u00e9 tentar sempre facilitar o seu entendimento sobre assuntos importantes da matem\u00e1tica.<br \/>\nContinue pesquisando sobre o assunto, afinal <strong>conhecimento nunca \u00e9 demais!<\/p>\n<\/td>\n<\/tr>\n<\/table>\n<p style=\"margin:20px\">\n<hr style=\"height:1px;background-color:#8B5A2B; border: 0 none\"\/>\n<hr style=\"height:1px;background-color:#8B5A2B; border: 0 none\"\/>\n<p style=\"text-align: center;\"><span style=\"color: #8B5A2B; font-size: 18px;\"><strong>Equipe COM &#8211; OBMEP<\/strong><\/span><\/p>\n<hr style=\"height:1px;background-color:#8B5A2B; border: 0 none\"\/>\n<hr style=\"height:1px;background-color:#8B5A2B; border: 0 none\"\/>\n","protected":false},"excerpt":{"rendered":"<p>Setor circular e segmento circular Vamos discutir sobre duas regi\u00f5es de um c\u00edrculo que, embora sejam bastante utilizadas na solu\u00e7\u00e3o de problemas envolvendo \u00e1reas, \u00e9 comum certa confus\u00e3o entre elas. Ambas as regi\u00f5es dependem de uma circunfer\u00eancia e de um \u00e2ngulo central (ou um arco de circunfer\u00eancia), elas t\u00eam uma rela\u00e7\u00e3o entre si, mas s\u00e3o &hellip; <\/p>\n<p><a class=\"more-link btn\" href=\"https:\/\/clubes.obmep.org.br\/blog\/brincando-com-geometria-setor-e-segmento-circular\/\">Continue lendo<\/a><\/p>\n","protected":false},"author":2,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"template-onecolumn.php","meta":{"footnotes":""},"class_list":["post-82372","page","type-page","status-publish","hentry","nodate","item-wrap"],"_links":{"self":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages\/82372","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/comments?post=82372"}],"version-history":[{"count":25,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages\/82372\/revisions"}],"predecessor-version":[{"id":223561,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages\/82372\/revisions\/223561"}],"wp:attachment":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/media?parent=82372"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}