{"id":43182,"date":"2015-07-31T12:19:28","date_gmt":"2015-07-31T15:19:28","guid":{"rendered":"http:\/\/clubes.obmep.org.br\/blog\/?page_id=43182"},"modified":"2023-03-22T23:30:39","modified_gmt":"2023-03-23T02:30:39","slug":"problema-de-gincana-raiz-de-porcentagem","status":"publish","type":"page","link":"https:\/\/clubes.obmep.org.br\/blog\/problema-de-gincana-raiz-de-porcentagem\/","title":{"rendered":".Problema de Gincana:  Raiz de porcentagem?"},"content":{"rendered":"<p style=\"margin:10px\">\n<div class=\"g1n\"  style=\"line-height:40px;\"}>\n<p class=\"tit\" style=\"line-height:30px;margin:10px\">Problema<\/p>\n<hr style=\"height:1px; width:100%;background-color:#800000; margin-top: 10px; margin-bottom: 20px;border: 0 none\"\/>\nQuanto vale [tex]\\sqrt{1\\%}[\/tex]?<br \/>\n(A) [tex]0,1\\%[\/tex]<br \/>\n(B) [tex]\\dfrac{1}{2}\\%[\/tex]<br \/>\n(C) [tex]1\\%[\/tex]<br \/>\n(D) [tex]10\\%[\/tex]<br \/>\n(E) [tex]100\\%[\/tex]<\/p>\n<p style=\"margin:10px\">\n<\/div>\n<p style=\"margin:30px\">\n<div class=\"g1n\">\n<p class=\"tit\" style=\"line-height:30px;margin:10px\">Solu\u00e7\u00e3o<\/p>\n<hr style=\"height:1px; width:100%;background-color:#800000; margin-top: 10px; margin-bottom: 20px;border: 0 none\"\/>\nObservem que:<br \/>\n [tex]\\qquad\\qquad \\sqrt{1\\%} = \\sqrt{\\dfrac{1}{100}}=\\dfrac{1}{10}=\\dfrac{10}{100}=10\\%[\/tex].<\/p>\n<p style=\"margin:10px\">\n<p>Assim, [tex]\\boxed{\\sqrt{1\\%} = 10\\%}[\/tex].<\/p>\n<hr style=\"height:1px; width:100%;background-color:#800000; margin-top: 10px; margin-bottom: 15px;border: 0 none\"\/>\n<p class=\"g2\" style=\"line-height:20px;\">Solu\u00e7\u00e3o elaborada pelos <strong>Moderadores do Blog<\/strong>.<\/p>\n<\/div>\n<p style=\"margin:30px\">\n<div class=\"gg\">\nSegunda Gincana de 2015 &#8211; Clubes de Matem\u00e1tica da OBMEP<br \/>\nN\u00edvel A &#8211; Quest\u00e3o F\u00e1cil<\/div>\n","protected":false},"excerpt":{"rendered":"<p>Problema Quanto vale [tex]\\sqrt{1\\%}[\/tex]? (A) [tex]0,1\\%[\/tex] (B) [tex]\\dfrac{1}{2}\\%[\/tex] (C) [tex]1\\%[\/tex] (D) [tex]10\\%[\/tex] (E) [tex]100\\%[\/tex] Solu\u00e7\u00e3o Observem que: [tex]\\qquad\\qquad \\sqrt{1\\%} = \\sqrt{\\dfrac{1}{100}}=\\dfrac{1}{10}=\\dfrac{10}{100}=10\\%[\/tex]. Assim, [tex]\\boxed{\\sqrt{1\\%} = 10\\%}[\/tex]. Solu\u00e7\u00e3o elaborada pelos Moderadores do Blog. Segunda Gincana de 2015 &#8211; Clubes de Matem\u00e1tica da OBMEP N\u00edvel A &#8211; Quest\u00e3o F\u00e1cil<\/p>\n","protected":false},"author":2,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"open","ping_status":"closed","template":"template-onecolumn.php","meta":{"footnotes":""},"class_list":["post-43182","page","type-page","status-publish","hentry","nodate","item-wrap"],"_links":{"self":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages\/43182","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/comments?post=43182"}],"version-history":[{"count":17,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages\/43182\/revisions"}],"predecessor-version":[{"id":185138,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages\/43182\/revisions\/185138"}],"wp:attachment":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/media?parent=43182"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}