{"id":41679,"date":"2015-07-03T13:48:08","date_gmt":"2015-07-03T16:48:08","guid":{"rendered":"http:\/\/clubes.obmep.org.br\/blog\/?page_id=41679"},"modified":"2023-03-22T23:34:43","modified_gmt":"2023-03-23T02:34:43","slug":"problema-de-gincana-texsenostex-e-texcossenostex","status":"publish","type":"page","link":"https:\/\/clubes.obmep.org.br\/blog\/problema-de-gincana-texsenostex-e-texcossenostex\/","title":{"rendered":".Problema de Gincana:  Senos e cossenos"},"content":{"rendered":"<p style=\"margin:10px\">\n<div class=\"g1n\">\n<p class=\"tit\" style=\"line-height:30px;margin:10px\">Problema<\/p>\n<hr style=\"height:1px; width:100%;background-color:#800000; margin-top: 10px; margin-bottom: 20px;border: 0 none\"\/>\nSe [tex]sen(x) + cos(x) = m[\/tex], ent\u00e3o [tex]sen(2x)[\/tex] \u00e9 igual a:<\/p>\n<p>(A) [tex]2m[\/tex].<\/p>\n<p>(B) [tex]m^2[\/tex].<\/p>\n<p>(C) [tex]m^2 &#8211; 1[\/tex].<\/p>\n<p>(D) [tex]m &#8211; 1[\/tex].<\/p>\n<p>(E) [tex]m^2 &#8211; m[\/tex].<\/p><\/div>\n<p style=\"margin:30px\">\n<div class=\"g1n\" style=\"line-height:30px;\">\n<p class=\"tit\" style=\"line-height:30px;margin:10px\">Solu\u00e7\u00e3o<\/p>\n<hr style=\"height:1px; width:100%;background-color:#800000; margin-top: 10px; margin-bottom: 20px;border: 0 none\"\/>\nSeja [tex]sen(x) + cos(x) = m[\/tex]; ent\u00e3o segue que:<br \/>\n[tex]\\qquad sen(x) + cos(x) = m \\\\<br \/>\n\\qquad(sen(x) + cos(x))^2 = m^2 \\\\<br \/>\n\\qquad  sen^2(x) + 2 \\cdot sen(x) \\cdot cos(x)+cos^2(x) = m^2\\\\<br \/>\n\\qquad  \\left(sen^2(x) + cos^2(x)\\right) + 2 \\cdot sen(x) \\cdot cos(x) = m^2\\,.[\/tex]<br \/>\nComo [tex]\\boxed{sen(2x) = 2 \\cdot sen(x) \\cdot cos(x)}\\;[\/tex] e [tex]\\;\\boxed{sen^2(x) + cos^2(x) = 1}[\/tex], segue, da \u00faltima igualdade, que<br \/>\n[tex]\\qquad 1 + sen(2x) = m^2[\/tex],<br \/>\ne, finalmente, conclu\u00edmos que<br \/>\n[tex]\\qquad \\fcolorbox{black}{#eee0e5}{$sen(2x) = m^2 &#8211; 1$}\\,[\/tex].<\/p>\n<hr style=\"height:1px; width:100%;background-color:#800000; margin-top: 10px; margin-bottom: 15px;border: 0 none\"\/>\n<p class=\"g2\" >Solu\u00e7\u00e3o elaborada pelos <strong>Moderadores do Blog<\/strong>.<\/p>\n<\/div>\n<p style=\"margin:30px\">\n<div class=\"gg\">\nPrimeira Gincana de 2015 &#8211; Clubes de Matem\u00e1tica da OBMEP<br \/>\nN\u00edvel C &#8211; Quest\u00e3o F\u00e1cil<\/div>\n","protected":false},"excerpt":{"rendered":"<p>Problema Se [tex]sen(x) + cos(x) = m[\/tex], ent\u00e3o [tex]sen(2x)[\/tex] \u00e9 igual a: (A) [tex]2m[\/tex]. (B) [tex]m^2[\/tex]. (C) [tex]m^2 &#8211; 1[\/tex]. (D) [tex]m &#8211; 1[\/tex]. (E) [tex]m^2 &#8211; m[\/tex]. Solu\u00e7\u00e3o Seja [tex]sen(x) + cos(x) = m[\/tex]; ent\u00e3o segue que: [tex]\\qquad sen(x) + cos(x) = m \\\\ \\qquad(sen(x) + cos(x))^2 = m^2 \\\\ \\qquad sen^2(x) + 2 &hellip; <\/p>\n<p><a class=\"more-link btn\" href=\"https:\/\/clubes.obmep.org.br\/blog\/problema-de-gincana-texsenostex-e-texcossenostex\/\">Continue lendo<\/a><\/p>\n","protected":false},"author":2,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"open","ping_status":"closed","template":"template-onecolumn.php","meta":{"footnotes":""},"class_list":["post-41679","page","type-page","status-publish","hentry","nodate","item-wrap"],"_links":{"self":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages\/41679","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/comments?post=41679"}],"version-history":[{"count":18,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages\/41679\/revisions"}],"predecessor-version":[{"id":185147,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages\/41679\/revisions\/185147"}],"wp:attachment":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/media?parent=41679"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}