{"id":23047,"date":"2014-09-08T20:27:14","date_gmt":"2014-09-08T23:27:14","guid":{"rendered":"http:\/\/clubes.obmep.org.br\/blog\/?page_id=23047"},"modified":"2022-05-29T01:39:09","modified_gmt":"2022-05-29T04:39:09","slug":"principio-fundamental-de-contagem-conferindo","status":"publish","type":"page","link":"https:\/\/clubes.obmep.org.br\/blog\/sala-de-estudos-principio-fundamental-da-contagem\/principio-fundamental-de-contagem-conferindo\/","title":{"rendered":"Princ\u00edpio Fundamental da Contagem &#8211; Conferindo"},"content":{"rendered":"<p style=\"margin:20px;\">\n<div style=\"border: 8px double #BDB76B; padding: 10px;text-align:justify; padding-right:40px; padding-left: 40px;\">\n<p style=\"margin:20px;\">\n<table style=\" height:auto;text-align:justify;margin-left: auto; margin-right: auto; width:530px;\">\n<tr>\n<td class=\"bf\"><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-1001 alignrigth\" style=\"border: 0px;\" alt=\"\" src=\"http:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2013\/01\/menino.jpg\" width=\"95\" height=\"115\" \/><\/td>\n<td class=\"bf\">\n<p class=\"fala\" style=\"width:400px;background-color: #CDC673;\" >Voc\u00eas j\u00e1 resolveram os problemas da Mega-Sena, das placas e dos fragmentos de DNA?<br \/>\nEnt\u00e3o, confiram as respostas!<\/p>\n<\/td>\n<\/tr>\n<\/table>\n<p style=\"margin:40px;\">\n<div style=\"border: 2px solid #BDB76B; padding: 8px;padding-right: 30px; padding-left:30px;\">\n<p class=\"ti2\" style=\"color: #BDB76B;line-height:25px;margin:10px\"><em>Fragmentos de DNA<\/em><\/p>\n<hr style=\"height:2px; background-color:#BDB76B; border: 0 none\"\/>\n<p style=\"margin:40px;\">\n<div style=\"font-size: medium; font-family: Calibri, sans-serif; color: #1c1c1c; border: 2px solid #000000; padding: 10px; line-height: 20px;text-align:justify\">\n<strong>Problema:<\/strong><br \/>\nQuantos fragmentos diferentes de DNA podem ser sintetizados com dez pares de bases nitrogenadas de modo que um par <strong>A \u2013 T <\/strong>n\u00e3o esteja junto a um par <strong>T \u2013 A<\/strong> ou a outro par <strong>A \u2013 T<\/strong>, e que um par <strong>G \u2013 C<\/strong> n\u00e3o esteja junto a um par <strong>C \u2013 G<\/strong> ou a outro par <strong>G \u2013 C<\/strong>?\n<\/div>\n<p style=\"margin:20px;\">\n<div style=\"text-align:center;\">\n<input value=\"Ver a solu\u00e7\u00e3o\" style=\"padding: 0px; width: 150px; height: 40px; background-color:#BDB76B; font-size: 18px; font-family: Calibri, sans-serif; color: #ffffff;\" onclick=    \"if(this.parentNode.getElementsByTagName('div')[0].style.display != ''){this.parentNode.getElementsByTagName('div')[0].style.display = '';this.value = 'Ocultar a solu\u00e7\u00e3o';} else{this.parentNode.getElementsByTagName('div')[0].style.display = 'none'; this.value = 'Ver a solu\u00e7\u00e3o';}\"    type=\"button\" \/>    <\/p>\n<div style=\"display: none;\">\n<div style=\"font-size: medium; font-family: Calibri, sans-serif; color: #1c1c1c; border: 1px dotted #000000;padding: 10px; line-height: 20px;text-align:justify\">\n<strong>Solu\u00e7\u00e3o: <\/strong><br \/>\nObserve que:<\/p>\n<ul>\n<li>h\u00e1 4 possibilidades para o primeiro par de bases;<\/li>\n<li>para o pr\u00f3ximo, haver\u00e1 2 possibilidades;<\/li>\n<li>escolhido este segundo par, haver\u00e1 2 possibilidades para o pr\u00f3ximo, e assim por diante.<\/li>\n<\/ul>\n<p>A quantidade total de possibilidades ser\u00e1, portanto, [tex]4\\cdot2^9=2^{11}=2048[\/tex].\n<\/p><\/div>\n<\/div>\n<\/div>\n<p style=\"margin:20px;\">\n<\/div>\n<p style=\"margin:40px\">\n<hr style=\"height:1px; width:50%;background-color:#BDB76B;  margin-top: 8px; margin-bottom: 8px; border: 0 none\"\/>\n<hr style=\"height:2px; width:60%;background-color:#BDB76B; margin-top: 8px; margin-bottom: 8px;  border: 0 none\"\/>\n<hr style=\"height:3px; width:70%;background-color:#BDB76B; margin-top: 8px; margin-bottom: 8px;  border: 0 none\"\/>\n<hr style=\"height:4px; width:75%;background-color:#BDB76B; margin-top: 8px; margin-bottom: 8px;  border: 0 none\"\/>\n<hr style=\"height:3px; width:70%;background-color:#BDB76B; margin-top: 8px; margin-bottom: 8px;  border: 0 none\"\/>\n<hr style=\"height:2px; width:60%;background-color:#BDB76B; margin-top: 8px; margin-bottom: 8px;  border: 0 none\"\/>\n<hr style=\"height:1px; width:50%;background-color:#BDB76B;  margin-top: 8px; margin-bottom: 8px; border: 0 none\"\/>\n<p style=\"margin:40px\">\n<div style=\"border: 2px solid #BDB76B; padding: 8px;padding-right: 30px; padding-left:30px;\">\n<p class=\"ti2\" style=\"color: #BDB76B;line-height:25px;margin:10px\"><em>Mural hist\u00f3rico<\/em><\/p>\n<hr style=\"height:2px; background-color:#BDB76B; border: 0 none\"\/>\n<p style=\"margin:40px;\">\n<div style=\"font-size: medium; font-family: Calibri, sans-serif; color: #1c1c1c; border: 2px solid #000000; padding: 10px; line-height: 20px;text-align:justify\">\n<strong>Problema (a):<\/strong><br \/>\nQuantas placas de autom\u00f3veis podem ser feitas com 6 d\u00edgitos?\n<\/div>\n<p style=\"margin:20px;\">\n<div style=\"text-align:center;\">\n<input  value=\"Ver a solu\u00e7\u00e3o\" style=\"padding: 0px; width: 150px; height: 40px; background-color:#BDB76B; font-size: 18px; font-family: Calibri, sans-serif; color: #ffffff;\" onclick=    \"if(this.parentNode.getElementsByTagName('div')[0].style.display != ''){this.parentNode.getElementsByTagName('div')[0].style.display = '';this.value = 'Ocultar a solu\u00e7\u00e3o';} else{this.parentNode.getElementsByTagName('div')[0].style.display = 'none'; this.value = 'Ver a solu\u00e7\u00e3o';}\"    type=\"button\" \/>    <\/p>\n<div  style=\"display: none;\">\n<div style=\"font-size: medium; font-family: Calibri, sans-serif; color: #1c1c1c; border: 1px dotted #000000;padding: 10px; line-height: 20px;text-align:justify\">\n<strong>Solu\u00e7\u00e3o: <\/strong><\/p>\n<ul>\n<li>H\u00e1 10 possibilidades para cada d\u00edgito (algarismo). <\/li>\n<\/ul>\n<p>Portanto, h\u00e1 [tex]10^6=1 000 000[\/tex] possibilidades de placas.\n<\/p><\/div>\n<\/div><\/div>\n<p style=\"margin:40px;\">\n<hr style=\"height:2px; background-color:#BDB76B; border: 0 none\"\/>\n<p style=\"margin:40px;\">\n<div style=\"font-size: medium; font-family: Calibri, sans-serif; color: #1c1c1c; border: 2px solid #000000; padding: 10px; line-height: 20px;text-align:justify\">\n<strong>Problema (b):<\/strong><br \/>\nQuantas placas de autom\u00f3veis podem ser feitas com 2 letras e 4 d\u00edgitos?\n<\/div>\n<p style=\"margin:20px;\">\n<div style=\"text-align:center;\">\n<input  value=\"Ver a solu\u00e7\u00e3o\" style=\"padding: 0px; width: 150px; height: 40px; background-color:#BDB76B; font-size: 18px; font-family: Calibri, sans-serif; color: #ffffff;\" onclick=    \"if(this.parentNode.getElementsByTagName('div')[0].style.display != ''){this.parentNode.getElementsByTagName('div')[0].style.display = '';this.value = 'Ocultar a solu\u00e7\u00e3o';} else{this.parentNode.getElementsByTagName('div')[0].style.display = 'none'; this.value = 'Ver a solu\u00e7\u00e3o';}\"    type=\"button\" \/>    <\/p>\n<div  style=\"display: none;\">\n<div style=\"font-size: medium; font-family: Calibri, sans-serif; color: #1c1c1c; border: 1px dotted #000000;padding: 10px; line-height: 20px;text-align:justify\">\n<strong>Solu\u00e7\u00e3o: <\/strong><\/p>\n<ul>\n<li>H\u00e1 10 possibilidades para cada d\u00edgito (algarismo).\n<\/li>\n<li>Para cada letra, h\u00e1 26 possibilidades.<\/li>\n<\/ul>\n<p> Portanto, h\u00e1 [tex]26^2\\cdot 10^4=6 760 000 [\/tex] possibilidades de placas.\n<\/p><\/div>\n<\/div>\n<\/div>\n<p style=\"margin:40px;\">\n<hr style=\"height:2px; background-color:#BDB76B; border: 0 none\"\/>\n<p style=\"margin:40px;\">\n<div style=\"font-size: medium; font-family: Calibri, sans-serif; color: #1c1c1c; border: 2px solid #000000; padding: 10px; line-height: 20px;text-align:justify\">\n<strong>Problema (c):<\/strong><br \/>\nQuantas placas de autom\u00f3veis podem ser feitas com 3 letras e 4 d\u00edgitos?\n<\/div>\n<p style=\"margin:20px;\">\n<div style=\"text-align:center;\">\n<input  value=\"Ver a solu\u00e7\u00e3o\" style=\"padding: 0px; width: 150px; height: 40px; background-color:#BDB76B; font-size: 18px; font-family: Calibri, sans-serif; color: #ffffff;\" onclick=    \"if(this.parentNode.getElementsByTagName('div')[0].style.display != ''){this.parentNode.getElementsByTagName('div')[0].style.display = '';this.value = 'Ocultar a solu\u00e7\u00e3o';} else{this.parentNode.getElementsByTagName('div')[0].style.display = 'none'; this.value = 'Ver a solu\u00e7\u00e3o';}\"    type=\"button\" \/>    <\/p>\n<div  style=\"display: none;\">\n<div style=\"font-size: medium; font-family: Calibri, sans-serif; color: #1c1c1c; border: 1px dotted #000000;padding: 10px; line-height: 20px;text-align:justify\">\n<strong>Solu\u00e7\u00e3o: <\/strong><\/p>\n<ul>\n<li>H\u00e1 10 possibilidades para cada d\u00edgito (algarismo). <\/li>\n<li>Para cada letra, h\u00e1 26 possibilidades.<\/li>\n<\/ul>\n<p> Portanto, h\u00e1 [tex] 26^3\\cdot 10^4=175 760 000  [\/tex] possibilidades de placas.\n<\/p><\/div>\n<\/div>\n<\/div>\n<p style=\"margin:40px;\">\n<hr style=\"height:2px; background-color:#BDB76B; border: 0 none\"\/>\n<p style=\"margin:40px;\">\n<div style=\"font-size: medium; font-family: Calibri, sans-serif; color: #1c1c1c; border: 2px solid #000000; padding: 10px; line-height: 20px;text-align:justify\">\n<strong>Problema (d):<\/strong><br \/>\nPor que acrescentar uma letra e n\u00e3o um d\u00edgito?\n<\/div>\n<p style=\"margin:20px;\">\n<div style=\"text-align:center;\">\n<input value=\"Ver a solu\u00e7\u00e3o\" style=\"padding: 0px; width: 150px; height: 40px; background-color:#BDB76B; font-size: 18px; font-family: Calibri, sans-serif; color: #ffffff;\" onclick=    \"if(this.parentNode.getElementsByTagName('div')[0].style.display != ''){this.parentNode.getElementsByTagName('div')[0].style.display = '';this.value = 'Ocultar a solu\u00e7\u00e3o';} else{this.parentNode.getElementsByTagName('div')[0].style.display = 'none'; this.value = 'Ver a solu\u00e7\u00e3o';}\"    type=\"button\" \/>    <\/p>\n<div  style=\"display: none;\">\n<div style=\"font-size: medium; font-family: Calibri, sans-serif; color: #1c1c1c; border: 1px dotted #000000;padding: 10px; line-height: 20px;text-align:justify\">\n<strong>Solu\u00e7\u00e3o: <\/strong><br \/>\nH\u00e1 10 possibilidades de d\u00edgitos e 26 possibilidades de letras.<br \/>\nAo acrescentar uma letra, o n\u00famero anterior de possibilidades fica multiplicado por 26:<strong> bem maior do que se fosse multiplicado por 10<\/strong>.\n<\/div>\n<\/div>\n<\/div>\n<p style=\"margin:40px;\">\n<hr style=\"height:2px; background-color:#BDB76B; border: 0 none\"\/>\n<p style=\"padding-left: 80px\">\n<table style=\" height:auto;text-align:justify;margin-left: auto; margin-right: auto; width:530px;\">\n<tr>\n<td class=\"bf\"><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-1001 alignrigth\" style=\"border: 0px;\" alt=\"\" src=\"http:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2013\/01\/menino.jpg\" width=\"95\" height=\"115\" \/><\/td>\n<td class=\"bf\">\n<p class=\"fala\" style=\"width:400px;background-color: #CDC673;\" ><strong>Para pensar:<\/strong><br \/>\nRefa\u00e7am as contas, considerando que no Brasil n\u00e3o h\u00e1 placas com todos os d\u00edgitos iguais a 0.\n<\/td>\n<\/tr>\n<\/table>\n<\/div>\n<p style=\"margin:40px\">\n<hr style=\"height:1px; width:50%;background-color:#BDB76B;  margin-top: 8px; margin-bottom: 8px; border: 0 none\"\/>\n<hr style=\"height:2px; width:60%;background-color:#BDB76B;  margin-top: 8px; margin-bottom: 8px; border: 0 none\"\/>\n<hr style=\"height:3px; width:70%;background-color:#BDB76B; margin-top: 8px; margin-bottom: 8px;  border: 0 none\"\/>\n<hr style=\"height:4px; width:75%;background-color:#BDB76B; margin-top: 8px; margin-bottom: 8px;  border: 0 none\"\/>\n<hr style=\"height:3px; width:70%;background-color:#BDB76B; margin-top: 8px; margin-bottom: 8px;  border: 0 none\"\/>\n<hr style=\"height:2px; width:60%;background-color:#BDB76B; margin-top: 8px; margin-bottom: 8px;  border: 0 none\"\/>\n<hr style=\"height:1px; width:50%;background-color:#BDB76B; margin-top: 8px; margin-bottom: 8px;  border: 0 none\"\/>\n<p style=\"margin:40px\">\n<div style=\"border: 2px solid #BDB76B; padding: 8px;padding-right: 30px; padding-left:30px;\">\n<p class=\"ti2\" style=\"color: #BDB76B;line-height:25px;margin:10px\"><em>Azar<\/em><\/p>\n<hr style=\"height:2px; background-color:#BDB76B; border: 0 none\"\/>\n<div style=\"font-size: medium; font-family: Calibri, sans-serif; color: #1c1c1c; border: 2px solid #000000; padding: 10px; line-height: 20px;text-align:justify\">\n<strong>Problema:<\/strong><br \/>\nQuantas s\u00e3o as poss\u00edveis apostas para a Mega-Sena?\n<\/div>\n<p style=\"margin:40px;\">\n<div style=\"text-align:center;\">\n<input  value=\"Ver a solu\u00e7\u00e3o\" style=\"padding: 0px; width: 150px; height: 40px; background-color:#BDB76B; font-size: 18px; font-family: Calibri, sans-serif; color: #ffffff;\" onclick=    \"if(this.parentNode.getElementsByTagName('div')[0].style.display != ''){this.parentNode.getElementsByTagName('div')[0].style.display = '';this.value = 'Ocultar a solu\u00e7\u00e3o';} else{this.parentNode.getElementsByTagName('div')[0].style.display = 'none'; this.value = 'Ver a solu\u00e7\u00e3o';}\"    type=\"button\" \/>    <\/p>\n<div style=\"display: none;\">\n<div style=\"font-size: medium; font-family: Calibri, sans-serif; color: #1c1c1c; border: 1px dotted #000000;padding: 15px; line-height: 25px;text-align:justify\">\n<strong>Solu\u00e7\u00e3o: <\/strong><br \/>\nConforme sabemos, h\u00e1 60 dezenas, das quais s\u00e3o escolhidas 6. Para a primeira escolha, temos 60 possibilidades. Escolhida a primeira dezena, restam 59 possibilidades de escolha para a segunda. Escolhida a segunda, temos 58 possibilidades para a terceira escolha.<br \/>\n\tSeguindo esta linha de pensamento e utilizando o Princ\u00edpio Multiplicativo, encontramos<br \/>\n <span style=\"padding-left: 40px;\"> <strong>60x59x58x57x56x55=36 045 979 200<\/strong> possibilidades de apostas!<\/span><br \/>\n <span style=\"padding-left: 80px;line-height: 40px;\"><strong>Ser\u00e1?<\/strong><\/span><br \/>\n\tVamos tomar um exemplo. Imagine que voc\u00ea escolha as dezenas <strong>1, 10, 20, 30, 40 e 50,<\/strong> nesta ordem. \u00c9 uma possibilidade, certo? Agora, de acordo com o c\u00e1lculo que fizemos, escolhas como <strong>10, 20, 40, 50, 30 e 1<\/strong> ou <strong>30, 40, 50, 20, 1 e 10<\/strong> foram consideradas como outras possibilidades distintas, embora n\u00e3o seja assim! Na realidade, dada uma possibilidade de aposta, todas as suas permuta\u00e7\u00f5es foram consideradas, erroneamente, distintas.<br \/>\n<strong><em>Mas quantas s\u00e3o as permuta\u00e7\u00f5es de seis n\u00fameros?<\/em><br \/>\n<\/strong>N\u00f3s sabemos calcular: s\u00e3o 6!=720 permuta\u00e7\u00f5es.<br \/>\nAssim, cada aposta foi contada 720 vezes; portanto para que a quantidade fique correta, basta dividirmos o resultado encontrado por 720, o que resulta em:<br \/>\n <span style=\"padding-left: 40px;\"><strong>50 063 860 possibilidades de aposta para a Mega-Sena.<\/strong><\/span>\n<\/div>\n<\/div>\n<\/div>\n<p style=\"margin:20px;\">\n<\/div>\n<p style=\"margin:40px;\">\n<hr style=\"height:1px; background-color:#BDB76B; margin-top: 8px; margin-bottom: 8px;  border: 0 none\"\/>\n<hr style=\"height:1px; background-color:#BDB76B;  margin-top: 8px; margin-bottom: 8px; border: 0 none\"\/>\n<p style=\"text-align: right; padding-right: 10px;\"><span style=\"color: #BDB76B;\"><strong>&#8211; Francimar de Brito Vieira<\/strong><br \/>\n<strong>&#8211; Noemi Zeraick Monteiro<\/strong><br \/>\n<strong>&#8211; Sonia Regina Di Giacomo<\/strong><br \/>\n&#9670; Equipe COM &#8211; OBMEP<\/span><\/p>\n<\/div>\n<p style=\"text-align: right;\"><a href=\"http:\/\/clubes.obmep.org.br\/blog\/?p=22162\" title=\"Voltar\"><span style=\"color: #BDB76B;\"><strong>Voltar para a Sala de Estudos sobre o PFC<\/strong><\/span><\/a><\/p>\n<table style=\" height:auto;text-align:justify;margin-left: auto; margin-right: auto; width:530px;\">\n<tr>\n<td class=\"bf\">\n<p class=\"fala\" style=\"width:400px;background-color: #CDC673;\" >Mas e agora?<br \/>\nNosso estudo sobre o Princ\u00edpio Multiplicativo acabou?<\/p>\n<\/td>\n<td class=\"bf\"><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2014\/04\/carinha20.jpg\" style=\"border: 0px;\" alt=\"carinha20\" width=\"95\" height=\"88\" class=\"alignright size-full wp-image-17461\" \/><\/td>\n<\/tr>\n<\/table>\n<table style=\" height:auto;text-align:justify;margin-left: auto; margin-right: auto; width:644px;\">\n<tr>\n<td class=\"bf\"><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-1001 alignrigth\" style=\"border: 0px;\" alt=\"\" src=\"http:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2013\/01\/menino.jpg\" width=\"95\" height=\"115\" \/><\/td>\n<td class=\"bf\">\n<p class=\"fala\" style=\"width:520px;background-color: #CDC673;\" >Tudo que estudamos deve ser, sempre, aprofundado e aprimorado. Voc\u00ea continuar\u00e1 encontrando o PFC em livros, provas e em muitos outros lugares, inclusive aqui no Blog. Na Videoteca e na Sala de Leitura &#8211; Pequenos Textos, por exemplo, voc\u00ea pode encontrar outros materiais que utilizam ou falam sobre o PFC. Isso sem contar a Sala de Problemas, \u00e9 claro.<br \/>\nVisite a  <a href=\"http:\/\/clubes.obmep.org.br\/blog\/?p=23068\" title=\"Visite a Sala.\"><span style=\"color: #ffffff; letter-spacing: 1px;\"> <strong>\u00faltima Sala<\/strong><\/span><\/a> e verifique uma importante conex\u00e3o com o assunto tratado.<\/p>\n<\/td>\n<\/tr>\n<\/table>\n","protected":false},"excerpt":{"rendered":"<p>Voc\u00eas j\u00e1 resolveram os problemas da Mega-Sena, das placas e dos fragmentos de DNA? Ent\u00e3o, confiram as respostas! Fragmentos de DNA Problema: Quantos fragmentos diferentes de DNA podem ser sintetizados com dez pares de bases nitrogenadas de modo que um par A \u2013 T n\u00e3o esteja junto a um par T \u2013 A ou a &hellip; <\/p>\n<p><a class=\"more-link btn\" href=\"https:\/\/clubes.obmep.org.br\/blog\/sala-de-estudos-principio-fundamental-da-contagem\/principio-fundamental-de-contagem-conferindo\/\">Continue lendo<\/a><\/p>\n","protected":false},"author":2,"featured_media":0,"parent":22162,"menu_order":7,"comment_status":"closed","ping_status":"closed","template":"template-onecolumn.php","meta":{"footnotes":""},"class_list":["post-23047","page","type-page","status-publish","hentry","nodate","item-wrap"],"_links":{"self":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages\/23047","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/comments?post=23047"}],"version-history":[{"count":28,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages\/23047\/revisions"}],"predecessor-version":[{"id":180700,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages\/23047\/revisions\/180700"}],"up":[{"embeddable":true,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages\/22162"}],"wp:attachment":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/media?parent=23047"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}