{"id":205810,"date":"2023-12-08T02:42:17","date_gmt":"2023-12-08T05:42:17","guid":{"rendered":"http:\/\/clubes.obmep.org.br\/blog\/?page_id=205810"},"modified":"2023-12-08T03:55:22","modified_gmt":"2023-12-08T06:55:22","slug":"problema-cinco-retangulos","status":"publish","type":"page","link":"https:\/\/clubes.obmep.org.br\/blog\/problema-cinco-retangulos\/","title":{"rendered":".Problema: Cinco Ret\u00e2ngulos"},"content":{"rendered":"<p class=\"g2\" ><strong><a href=\"http:\/\/clubes.obmep.org.br\/blog\/?p=207615\" rel=\"noopener\" target=\"_blank\">&#9999; <span style=\"color:#A0522D;font-size:14px;\">Link do problema para dispositivos da <em>Apple<\/em>.<\/span><\/a><\/strong><\/p>\n<div class=\"g1n\" style=\"line-height:25px;padding-bottom:15px\">\n<p class=\"tit\" style=\"line-height:25px;margin:10px\">Problema<br \/>\n<span style=\"font-size:12px;color:#800000\"> (Indicado a partir do 7\u00ba ano do E. F.)<\/span><\/p>\n<hr style=\"height:1px; width:100%;background-color:#800000; margin-top: 10px; margin-bottom: 20px;border: 0 none\"\/>\n<p>Cinco ret\u00e2ngulos congruentes foram desenhados de forma a obtermos um ret\u00e2ngulo maior, conforme mostra a figura.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2023\/08\/Cinco-Ret\u00e2ngulos-1.png\" style=\"border:none;\" alt=\"\" width=\"479\" height=\"343\" class=\"aligncenter size-full wp-image-198373\" srcset=\"https:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2023\/08\/Cinco-Ret\u00e2ngulos-1.png 479w, https:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2023\/08\/Cinco-Ret\u00e2ngulos-1-300x215.png 300w\" sizes=\"auto, (max-width: 479px) 100vw, 479px\" \/><\/p>\n<p>Qual a \u00e1rea do ret\u00e2ngulo maior?<\/p>\n<p style=\"font-size: 12px;text-align:right;line-height:1px;\">Extra\u00eddo de <strong> Twitter<\/strong>.<\/p>\n<\/div>\n<p style=\"margin:40px\">\n<div class=\"g1n\" style=\"line-height:28px;\">\n<p class=\"tit\" style=\"line-height:28px;margin:10px\">Solu\u00e7\u00e3o<\/p>\n<hr style=\"height:1px; width:100%;background-color:#800000; margin-top: 1px; margin-bottom: 20px;border: 0 none\"\/>\n<p>Sejam [tex]~m~[\/tex] e [tex]~5-m[\/tex] as medidas das dimens\u00f5es de cada ret\u00e2ngulo. Observe a figura abaixo.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2023\/08\/Cinco-Ret\u00e2ngulos-2.png\" style=\"border:none;\" alt=\"\" width=\"567\" height=\"411\" class=\"aligncenter size-full wp-image-198374\" srcset=\"https:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2023\/08\/Cinco-Ret\u00e2ngulos-2.png 567w, https:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2023\/08\/Cinco-Ret\u00e2ngulos-2-300x217.png 300w\" sizes=\"auto, (max-width: 567px) 100vw, 567px\" \/><\/p>\n<p>A partir da\u00ed, podemos escrever:<br \/>\n[tex]\\qquad 3 \\cdot m=2 \\cdot (5-m)\\\\<br \/>\n\\qquad3 \\cdot m=10-2 \\cdot m\\\\<br \/>\n\\qquad 5 \\cdot m=10\\\\<br \/>\n\\qquad m=2.[\/tex]<\/p>\n<p>Desta forma, a \u00e1rea do ret\u00e2ngulo maior \u00e9 dada por:<br \/>\n [tex]\\qquad 5 \\cdot (3 \\cdot m)=30[\/tex] unidades de \u00e1rea.<\/p>\n<hr style=\"height:1px; width:100%;background-color:#800000; margin-top: 10px; margin-bottom: 15px;border: 0 none\"\/>\n<p class=\"g2\" >Solu\u00e7\u00e3o elaborada pelos <strong>Moderadores do Blog<\/strong>.<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"g3\">\nParticiparam da discuss\u00e3o os Clubes: <strong>Puzzlers [tex]\\pi[\/tex]rados<\/strong> ; <strong>Numeradores<\/strong> ; <strong>Geomestres Slay<\/strong> ; <strong>Pot\u00eancias de Euler<\/strong> ; <strong>Phidias<\/strong> ; <strong>Exponenciais<\/strong> ; <strong>Os \u00daltimos Alunos de Fermat<\/strong> ; <strong>Obm\u00e9picos<\/strong> ; <strong>Amigoritmos<\/strong> ; <strong>Super G\u00eanios [tex]3^\\circ[\/tex] CPM<\/ strong> ; <strong>Fibonacci<\/strong> ; <strong>Uni\u00e3o Fibonacci<\/strong> ; <strong>Lapidando Vencedores Matem\u00e1ticos<\/strong>.\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>&#9999; Link do problema para dispositivos da Apple. Problema (Indicado a partir do 7\u00ba ano do E. F.) Cinco ret\u00e2ngulos congruentes foram desenhados de forma a obtermos um ret\u00e2ngulo maior, conforme mostra a figura. Qual a \u00e1rea do ret\u00e2ngulo maior? Extra\u00eddo de Twitter. Solu\u00e7\u00e3o Sejam [tex]~m~[\/tex] e [tex]~5-m[\/tex] as medidas das dimens\u00f5es de cada ret\u00e2ngulo. &hellip; <\/p>\n<p><a class=\"more-link btn\" href=\"https:\/\/clubes.obmep.org.br\/blog\/problema-cinco-retangulos\/\">Continue lendo<\/a><\/p>\n","protected":false},"author":164,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"template-onecolumn.php","meta":{"footnotes":""},"class_list":["post-205810","page","type-page","status-publish","hentry","nodate","item-wrap"],"_links":{"self":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages\/205810","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/users\/164"}],"replies":[{"embeddable":true,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/comments?post=205810"}],"version-history":[{"count":10,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages\/205810\/revisions"}],"predecessor-version":[{"id":207618,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages\/205810\/revisions\/207618"}],"wp:attachment":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/media?parent=205810"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}