{"id":15652,"date":"2014-03-03T03:42:46","date_gmt":"2014-03-03T06:42:46","guid":{"rendered":"http:\/\/clubes.obmep.org.br\/blog\/?page_id=15652"},"modified":"2023-01-25T08:58:28","modified_gmt":"2023-01-25T11:58:28","slug":"probleminha-divida-o-relogio","status":"publish","type":"page","link":"https:\/\/clubes.obmep.org.br\/blog\/probleminha-divida-o-relogio\/","title":{"rendered":".Probleminha: Divida o rel\u00f3gio"},"content":{"rendered":"<p style=\"margin:10px\">\n<div class=\"g1n\">\n<p class=\"tit\"\n\n<p class=\"tit\" style=\"line-height:25px;margin:10px\">Problema<br \/>\n<span style=\"font-size:12px;color:#800000\"> (Indicado a partir do 6\u00ba ano do E. F.)<\/span><\/p>\n<hr style=\"height:1px; width:100%;background-color:#800000; margin-top: 10px; margin-bottom: 20px;border: 0 none\"\/>\nComo dividir o mostrador do rel\u00f3gio que aparece na figura abaixo em quatro partes, de modo que a soma dos n\u00fameros que ficar\u00e3o em cada parte seja a mesma?<br \/>\n<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2014\/03\/rel\u00f3gio.jpg\" style=\"border: 0px;\" alt=\"rel\u00f3gio\" width=\"464\" height=\"464\" class=\"aligncenter size-full wp-image-16825\" \/><\/div>\n<p style=\"margin:30px\">\n<div class=\"g1n\">\n<p class=\"tit\"\n\n<p class=\"tit\" style=\"line-height:28px;margin:10px\">Solu\u00e7\u00e3o<\/p>\n<hr style=\"height:1px; width:100%;background-color:#800000; margin-top: 10px; margin-bottom: 20px;border: 0 none\"\/>\nA soma dos n\u00fameros do mostrador \u00e9 78 (1+2+3+4+5+6+7+8+<span style=\" color: #0000CD;\"><strong>9<\/strong><\/span>+10+11+12=78), que n\u00e3o \u00e9 divis\u00edvel por 4.<br \/>\nEntretanto, se dividirmos o <span style=\" color: #0000CD;\"><strong>IX<\/strong><\/span> em <span style=\" color: #FF0000;\"><strong>I<\/strong><\/span> e <span style=\" color: #FF0000;\"><strong>X<\/strong><\/span> teremos aumentado em duas unidades o valor da soma  (1+2+3+4+5+6+7+8+<span style=\" color: #FF0000;\"><strong>(1+10)<\/strong><\/span>+10+11+12=80) e poderemos realizar a divis\u00e3o (80&#247;4=20).<br \/>\nVeja a figura a seguir.<br \/>\n<img loading=\"lazy\" decoding=\"async\" src=\"http:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2022\/12\/f252_1.png\" style=\"border: 0px;\" alt=\"\" width=\"420\" height=\"467\" class=\"aligncenter size-full wp-image-182188\" \/><\/p>\n<hr style=\"height:1px; width:100%;background-color:#800000; margin-top: 10px; margin-bottom: 15px;border: 0 none\"\/>\n<p class=\"g2\" style=\"line-height:20px;\">Solu\u00e7\u00e3o elaborada pelos <strong> Moderadores do Blog<\/strong>.<\/p>\n<\/div>\n<p style=\"margin:30px\">\n<div class=\"g3\"> Participou da discuss\u00e3o o Clube <strong>C\u00f3digos Infinitos<\/strong>.<\/div>\n","protected":false},"excerpt":{"rendered":"","protected":false},"author":179,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"open","ping_status":"closed","template":"template-onecolumn.php","meta":{"footnotes":""},"class_list":["post-15652","page","type-page","status-publish","hentry","nodate","item-wrap"],"_links":{"self":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages\/15652","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/users\/179"}],"replies":[{"embeddable":true,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/comments?post=15652"}],"version-history":[{"count":24,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages\/15652\/revisions"}],"predecessor-version":[{"id":183398,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages\/15652\/revisions\/183398"}],"wp:attachment":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/media?parent=15652"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}