{"id":141408,"date":"2019-11-16T02:03:40","date_gmt":"2019-11-16T04:03:40","guid":{"rendered":"http:\/\/clubes.obmep.org.br\/blog\/?page_id=141408"},"modified":"2023-06-09T04:22:49","modified_gmt":"2023-06-09T07:22:49","slug":"problema-criador-de-aves-exoticas","status":"publish","type":"page","link":"https:\/\/clubes.obmep.org.br\/blog\/problema-criador-de-aves-exoticas\/","title":{"rendered":".Problema: Criador de aves ex\u00f3ticas"},"content":{"rendered":"<p style=\"margin:10px\">\n<div class=\"g1n\" style=\"line-height:25px;\">\n<p class=\"tit\" style=\"line-height:20px;margin:10px\">Problema<br \/>\n<span style=\"font-size:12px;color:#800000\"> (Indicado a partir do 9\u00ba ano do E. F.)<\/span><\/p>\n<hr style=\"height:1px; width:100%;background-color:#800000; margin-top: 1px; margin-bottom: 20px;border: 0 none\"\/>\nDisse certo avicultor:<br \/>\n&#8211; \u201c<em>Quero com 100 reais comprar 100 aves; mas:<\/p>\n<li>cada Fais\u00e3o custa 10 reais; <\/li>\n<li>cada Can\u00e1rio custa 5 reais; <\/li>\n<li>e cada 2 Pintagol custa 1 real.<\/em>\u201d<\/li>\n<p>Diga quantas e quais aves devem ser comprados para que o pre\u00e7o seja exatamente 100 reais, nem mais nem menos?<\/p>\n<p style=\"margin:10px\">\n<\/div>\n<p style=\"margin:40px\">\n<div class=\"g1n\" style=\"line-height:28px;\">\n<p class=\"tit\" style=\"line-height:28px;margin:10px\">Solu\u00e7\u00e3o <\/p>\n<hr style=\"height:1px; width:100%;background-color:#800000; margin-top: 1px; margin-bottom: 20px;border: 0 none\"\/>\n<p>Vamos supor que [tex]x,\\ y\\ [\/tex] e [tex]\\ z[\/tex] sejam, respectivamente, as quantidades de fais\u00e3o, can\u00e1rio e pintagol a serem comprados.<br \/>\nAssim,  [tex]x,\\ y\\ [\/tex] e [tex] z [\/tex] s\u00e3o n\u00fameros naturais tais que:<\/p>\n<p>[tex]\\qquad \\qquad S:\\begin{cases} x+y+z=100\\\\ \\,\\,\\\\10x+5y+\\frac{z}{2}=100\\end{cases}[\/tex]<\/p>\n<p>O sistema [tex]S[\/tex] tem tr\u00eas vari\u00e1veis e duas equa\u00e7\u00f5es; portanto, conseguimos escrever duas vari\u00e1veis em fun\u00e7\u00e3o da terceira, veja:<\/p>\n<table class=\"bf\" style=\"width:99%\">\n<tr>\n<td class=\"bf\">[tex]\\quad \\begin{array}{r r r l}<br \/>\n \\cancel{-10x}&#038;-10y&#038;-10z&#038;=-1000\\\\<br \/>\n\\cancel{10x}&#038;+5y&#038;+\\frac{z}{2}&#038;=100\\\\<br \/>\n\\hline<br \/>\n&#038;-5y&#038;-\\frac{19}{2}z&#038;=-900\\\\<br \/>\n&#038;y&#038;+\\frac{19}{10}z&#038;=180\\\\<br \/>\n\\end{array}[\/tex] <\/td>\n<td class=\"bf\">[tex]\\quad \\begin{array}{r r r l}<br \/>\n-5x&#038; \\cancel{-5y}&#038;-5z&#038;=-500\\\\<br \/>\n10x&#038;+ \\cancel{5y}&#038;+\\frac{z}{2}&#038;=100\\\\<br \/>\n\\hline<br \/>\n5x&#038;&#038;-\\frac{9}{2}z&#038;=-400\\\\<br \/>\nx&#038; &#038;-\\frac{9}{10}z&#038;=-80\\\\<br \/>\n\\end{array}[\/tex]<\/td>\n<\/tr>\n<\/table>\n<p>e, assim, [tex]\\boxed{ x=\u221280+\\dfrac{9\\,z}{10}}\\quad [\/tex] e [tex]\\quad\\boxed{ y=180-\\dfrac{19\\,z}{10}}.[\/tex]<\/p>\n<p>Observe que  [tex]x[\/tex] e [tex] y[\/tex] s\u00e3o n\u00fameros naturais; assim, das express\u00f5es acima, conclu\u00edmos que <\/p>\n<ul>\n<li>[tex]z[\/tex] \u00e9 um m\u00faltiplo de [tex]10.  \\qquad \\qquad \\textcolor{#800000} {(i)} [\/tex]<\/li>\n<\/ul>\n<p>Por outro lado,  [tex]x\\geqslant 0[\/tex] e [tex]y \\geqslant  0[\/tex]; assim, temos:<\/p>\n<ul>\n<li>[tex] x=\u221280+\\frac{9z}{10}\\geqslant  0[\/tex], donde [tex] z\\geqslant  88,8 \\qquad \\qquad \\textcolor{#800000} {(ii)}[\/tex]<\/li>\n<\/ul>\n<p>e<\/p>\n<ul>\n<li>[tex]y=180-\\frac{19z}{10}\\geqslant  0[\/tex], donde [tex] z\\leqslant  94,7 .\\qquad \\qquad \\textcolor{#800000} {(iii)}[\/tex]<\/li>\n<\/ul>\n<p>De [tex]\\textcolor{#800000} {(i)}[\/tex], [tex]\\textcolor{#800000} {(ii)}[\/tex] e [tex] \\textcolor{#800000} {(iii)}[\/tex] conclu\u00edmos que [tex]z[\/tex] \u00e9 um m\u00faltiplo de [tex]10[\/tex], e portanto um n\u00famero inteiro, tal que [tex]\\,\\, 88,8 \\leqslant z\\leqslant  94,7[\/tex]; assim, [tex]\\,\\fcolorbox{black}{#eee0e5}{$z=90$}\\,[\/tex] e, consequentemente, [tex]\\,\\fcolorbox{black}{#eee0e5}{$x=1$}[\/tex] e [tex]\\,\\fcolorbox{black}{#eee0e5}{$y=9$}.[\/tex]<br \/>\n<strong>Logo, o comerciante dever\u00e1 comprar um fais\u00e3o, nove can\u00e1rios e noventa pintag\u00f3is.<\/strong><\/p>\n<hr style=\"height:1px; width:100%;background-color:#800000; margin-top: 10px; margin-bottom: 15px;border: 0 none\"\/>\n<p class=\"g2\" style=\"line-height:20px;\">Solu\u00e7\u00e3o elaborada pelos <strong>Moderadores do Blog<\/strong>.<\/p>\n<\/div>\n<p style=\"margin:30px\">\n<div class=\"g3\">\nParticiparam da discuss\u00e3o os Clubes: <strong>Grupo Napier<\/strong> e  <strong>OCTETO MATEM\u00c1TICO<\/strong>.<\/div>\n<p style=\"margin:10px\">\n","protected":false},"excerpt":{"rendered":"<p>Problema (Indicado a partir do 9\u00ba ano do E. F.) Disse certo avicultor: &#8211; \u201cQuero com 100 reais comprar 100 aves; mas: cada Fais\u00e3o custa 10 reais; cada Can\u00e1rio custa 5 reais; e cada 2 Pintagol custa 1 real.\u201d Diga quantas e quais aves devem ser comprados para que o pre\u00e7o seja exatamente 100 reais, &hellip; <\/p>\n<p><a class=\"more-link btn\" href=\"https:\/\/clubes.obmep.org.br\/blog\/problema-criador-de-aves-exoticas\/\">Continue lendo<\/a><\/p>\n","protected":false},"author":2,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"template-onecolumn.php","meta":{"footnotes":""},"class_list":["post-141408","page","type-page","status-publish","hentry","nodate","item-wrap"],"_links":{"self":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages\/141408","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/comments?post=141408"}],"version-history":[{"count":16,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages\/141408\/revisions"}],"predecessor-version":[{"id":193880,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages\/141408\/revisions\/193880"}],"wp:attachment":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/media?parent=141408"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}