{"id":13090,"date":"2014-01-27T14:23:55","date_gmt":"2014-01-27T16:23:55","guid":{"rendered":"http:\/\/clubes.obmep.org.br\/blog\/?page_id=13090"},"modified":"2023-01-13T02:47:44","modified_gmt":"2023-01-13T05:47:44","slug":"problema-olimpico-nivel-b-simplificando-potencias","status":"publish","type":"page","link":"https:\/\/clubes.obmep.org.br\/blog\/problema-olimpico-nivel-b-simplificando-potencias\/","title":{"rendered":".Problema Ol\u00edmpico &#8211; N\u00edvel B: Simplificando pot\u00eancias"},"content":{"rendered":"<div style=\"border: 3px solid #800000; padding: 10px;text-align: justify; padding-left: 12px; font-family: verdana; color: #616161; font-size: 15px; line-height: 25px;\">\n<p class=\"tit\" style=\"line-height:25px;margin:10px\"><strong>Problema<\/strong><\/p>\n<hr style=\"height:1px; width:100%;background-color:#800000; margin-top: 10px; margin-bottom: 20px;border: 0 none\"\/>\nDeterminar o valor de<br \/>\n [tex]\\qquad \\qquad \\quad \\dfrac{2^n\\times10^{n+2}}{5^{n+1}\\times4^n}[\/tex].<\/div>\n<p>&nbsp;<\/p>\n<div style=\"border: 3px  solid  #800000; padding: 10px; text-align: justify; padding-left: 12px; font-family: verdana; color: #616161; font-size: 15px; line-height: 25px;\">\n<p class=\"tit\" style=\"line-height:30px;margin:10px\"><strong>Solu\u00e7\u00e3o<\/strong><\/p>\n<hr style=\"height:1px; width:100%;background-color:#800000; margin-top: 10px; margin-bottom: 20px;border: 0 none\"\/>\nTemos que determinar o valor de [tex]\\dfrac{2^n\\times10^{n+2}}{5^{n+1}\\times4^n}[\/tex].<br \/>\nDas propriedades da potencia\u00e7\u00e3o, tem-se que [tex]\\fcolorbox{black}{yellow}{$ \\, a^n\\times a^m=a^{n+m} \\, $}\\,[\/tex]; ent\u00e3o, podemos escrever:<br \/>\n&nbsp;<br \/>\n[tex]\\qquad \\qquad \\dfrac{2^n\\times10^{n+2}}{4^n\\times5^{n+1}}=\\dfrac{2^n\\times10^n\\times10^2}{4^n\\times5^n\\times5}=\\dfrac{10^2}{5}\\,\\dfrac{2^n\\times10^n}{4^n\\times5^n}[\/tex].<br \/>\n&nbsp;<br \/>\nDe outra propriedade da potencia\u00e7\u00e3o, segue que [tex]\\fcolorbox{black}{yellow}{$ \\, a^n\\times b^n=(a\\times b)^n \\, $}\\,[\/tex]; assim, podemos escrever:<br \/>\n&nbsp;<br \/>\n[tex]\\qquad \\qquad \\dfrac{10^2}{5}\\dfrac{2^n\\times10^n}{4^n\\times5^n}=\\dfrac{100}{5}\\,\\dfrac{(2\\times10)^n}{(4\\times5)^n}=20\\dfrac{20^n}{20^n}=20[\/tex].<br \/>\n&nbsp;<br \/>\nPortanto,<br \/>\n[tex]\\qquad \\qquad \\fbox{$ \\, \\dfrac{2^n\\times10^{n+2}}{5^{n+1}\\times4^n}=20 \\, $}[\/tex].<\/p>\n<hr style=\"height:1px; width:100%;background-color:#800000; margin-top: 10px; margin-bottom: 15px;border: 0 none\"\/>\n<p class=\"g2\" style=\"line-height:20px;\">Solu\u00e7\u00e3o elaborada pelo aluno do PIC-OBMEP <strong>Andr\u00e9 Oliveira Mendes<\/strong>, com contribui\u00e7\u00f5es dos <strong>Moderadores do Blog. <\/strong><\/p>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>Problema Determinar o valor de [tex]\\qquad \\qquad \\quad \\dfrac{2^n\\times10^{n+2}}{5^{n+1}\\times4^n}[\/tex]. &nbsp; Solu\u00e7\u00e3o Temos que determinar o valor de [tex]\\dfrac{2^n\\times10^{n+2}}{5^{n+1}\\times4^n}[\/tex]. Das propriedades da potencia\u00e7\u00e3o, tem-se que [tex]\\fcolorbox{black}{yellow}{$ \\, a^n\\times a^m=a^{n+m} \\, $}\\,[\/tex]; ent\u00e3o, podemos escrever: &nbsp; [tex]\\qquad \\qquad \\dfrac{2^n\\times10^{n+2}}{4^n\\times5^{n+1}}=\\dfrac{2^n\\times10^n\\times10^2}{4^n\\times5^n\\times5}=\\dfrac{10^2}{5}\\,\\dfrac{2^n\\times10^n}{4^n\\times5^n}[\/tex]. &nbsp; De outra propriedade da potencia\u00e7\u00e3o, segue que [tex]\\fcolorbox{black}{yellow}{$ \\, a^n\\times b^n=(a\\times b)^n \\, $}\\,[\/tex]; assim, podemos escrever: &hellip; <\/p>\n<p><a class=\"more-link btn\" href=\"https:\/\/clubes.obmep.org.br\/blog\/problema-olimpico-nivel-b-simplificando-potencias\/\">Continue lendo<\/a><\/p>\n","protected":false},"author":2,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"template-onecolumn.php","meta":{"footnotes":""},"class_list":["post-13090","page","type-page","status-publish","hentry","nodate","item-wrap"],"_links":{"self":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages\/13090","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/comments?post=13090"}],"version-history":[{"count":26,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages\/13090\/revisions"}],"predecessor-version":[{"id":182877,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages\/13090\/revisions\/182877"}],"wp:attachment":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/media?parent=13090"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}