{"id":107486,"date":"2018-07-30T17:25:11","date_gmt":"2018-07-30T20:25:11","guid":{"rendered":"http:\/\/clubes.obmep.org.br\/blog\/?page_id=107486"},"modified":"2024-06-02T04:28:16","modified_gmt":"2024-06-02T07:28:16","slug":"problema-para-ajudar-na-escola-numeros-primos-em-um-conjunto","status":"publish","type":"page","link":"https:\/\/clubes.obmep.org.br\/blog\/problema-para-ajudar-na-escola-numeros-primos-em-um-conjunto\/","title":{"rendered":".Problema para ajudar na escola: N\u00fameros primos em um conjunto"},"content":{"rendered":"<p class=\"g2\" ><strong><a href=\"http:\/\/clubes.obmep.org.br\/blog\/?p=219641\" rel=\"noopener\" target=\"_blank\">&#9999; <span style=\"color:#A0522D;font-size:14px;\">Link do problema para dispositivos da <em>Apple<\/em>.<\/span><\/a><\/strong><\/p>\n<div class=\"g1n\" style=\"line-height:25px;\">\n<p class=\"tit\" style=\"line-height:25px;margin:10px\">Problema<br \/>\n<span style=\"font-size:12px;color:#00BF00\"> (A partir do 8\u00ba ano do E. F. &#8211; <span style=\"font-weight: normal;\"> N\u00edvel de dificuldade: M\u00e9dio<\/span>)<\/span><\/p>\n<hr style=\"height:1px; width:100%;background-color:#800000; margin-top: 10px; margin-bottom: 20px;border: 0 none\"\/>\n<p>Seja [tex]A=\\{1, \\, 2, \\, 3, \\, 4, \\, 5, \\, 6, \\, 7, \\, 8, \\, 9, \\, 10, \\, 11, \\, 12, \\, 13, \\, 14, \\, 15 \\} \\, .[\/tex]<br \/>\nDeterminar o menor inteiro positivo [tex]m[\/tex] tal que qualquer subconjunto de [tex]A[\/tex] com [tex]m[\/tex] elementos tenha, pelo menos, um n\u00famero primo.<\/p>\n<p style=\"margin:10px\">\n<\/div>\n<p style=\"margin:30px\">\n<div class=\"g1n\" style=\"line-height:26px;\">\n<p class=\"tit\" style=\"line-height:30px;margin:10px\">Solu\u00e7\u00e3o<\/p>\n<hr style=\"height:1px; width:100%;background-color:#800000; margin-top: 10px; margin-bottom: 20px;border: 0 none\"\/>\n<p>Observe que no conjunto [tex]A[\/tex] temos n\u00fameros primos e n\u00fameros n\u00e3o primos:<\/p>\n<ul>\n<li> <span class=\"c3\"> <strong>primos:[tex] \\, 2, \\, 3, \\, 5, \\, 7, \\, 11, \\, 13 \\, [\/tex]<\/strong><\/span>, <\/li>\n<li> <span class=\"c9\"><strong>n\u00e3o primos:[tex] \\, 1, \\, 4, \\, 6, \\, 8, \\, 9, \\, 10, \\, 12, \\, 14, \\, 15 \\, [\/tex]<\/strong><\/span>. <\/li>\n<\/ul>\n<p style=\"margin:10px\">\n<p><span style=\"font-size:11px;\">(O n\u00famero [tex]1[\/tex] n\u00e3o \u00e9 primo nem composto, por isso \u00e9 que separamos os n\u00fameros do  conjunto [tex]A[\/tex] em primos e n\u00e3o primos e n\u00e3o em primos e compostos.)<\/span><br \/>\nObserve, agora, que o maior subconjunto de [tex]A[\/tex] com n\u00fameros n\u00e3o primos \u00e9 exatamente<br \/>\n[tex]\\qquad \\qquad B=\\{1, \\, 4, \\, 6, \\, 8, \\, 9, \\, 10, \\, 12, \\, 14, \\, 15\\} \\, [\/tex];<br \/>\nassim, podemos concluir que<\/p>\n<ul>\n<li><strong> &quot; Se considerarmos conjuntos com mais de nove elementos, ent\u00e3o necessariamente esses conjuntos ter\u00e3o, pelo menos um n\u00famero primo &quot;.<\/strong><\/li>\n<\/ul>\n<p>N\u00e3o conseguiu se convencer da veracidade da afirma\u00e7\u00e3o?<br \/>\nEnt\u00e3o, pensemos juntos. <\/p>\n<ul>\n<li>Vamos tentar definir um subconjunto [tex]S[\/tex] de [tex]A[\/tex] com dez elementos, formado apenas de n\u00fameros n\u00e3o primos:<\/li>\n<p style=\"text-align:center, font-size:13px;\">\n[tex]S=\\{ \\,  \\, \\underline{\\quad } \\, , \\, \\underline{\\quad } \\, , \\, \\underline{\\quad } \\, , \\, \\underline{\\quad } \\, , \\, \\underline{\\quad } \\, , \\, \\underline{\\quad } \\, , \\, \\underline{\\quad } \\, , \\, \\underline{\\quad } \\, , \\, \\underline{\\quad } \\, , \\, \\underline{\\quad } \\,  \\, \\}[\/tex]\n<\/p>\n<p>Como poder\u00edamos preencher os dez espa\u00e7os?<br \/>\nBom, iniciemos o preenchimento com os n\u00fameros n\u00e3o primos de [tex]A[\/tex]:<\/p>\n<p style=\"text-align:center\"> [tex]S=\\{ \\,  \\, \\underline{\\textcolor{#6cda00}{1}} \\, , \\, \\underline{\\textcolor{#6cda00}{4} } \\, , \\, \\underline{\\textcolor{#6cda00}{6}} \\, , \\, \\underline{\\textcolor{#6cda00}{8} } \\, , \\, \\underline{\\textcolor{#6cda00}{9}} \\, , \\, \\underline{\\textcolor{#6cda00}{10}} \\, , \\, \\underline{\\textcolor{#6cda00}{12}} \\, , \\, \\underline{\\textcolor{#6cda00}{14}} \\, , \\, \\underline{\\textcolor{#6cda00}{15}} \\, , \\, \\underline{ \\,  \\, ? \\,  \\, } \\,  \\, \\}[\/tex]<\/p>\n<p>E agora, como preencheremos a \u00faltima lacuna???<br \/>\nN\u00e3o tem jeito, n\u00e3o \u00e9? S\u00f3 sobraram os n\u00fameros primos de [tex]A[\/tex]<\/p>\n<p style=\"text-align:center\"> [tex]S=\\{ \\, \\underline{\\textcolor{#6cda00}{1}} \\, , \\, \\underline{\\textcolor{#6cda00}{4} } \\, , \\, \\underline{\\textcolor{#6cda00}{6}} \\, , \\, \\underline{\\textcolor{#6cda00}{8} } \\, , \\, \\underline{\\textcolor{#6cda00}{9}} \\, , \\, \\underline{\\textcolor{#6cda00}{10}} \\, , \\, \\underline{\\textcolor{#6cda00}{12}} \\, , \\, \\underline{\\textcolor{#6cda00}{14}} \\, , \\, \\underline{\\textcolor{#6cda00}{15}} \\, , \\, \\underline{ \\,  \\, \\textcolor{#800000}{primo} \\,  \\, } \\, \\}[\/tex]<\/p>\n<\/ul>\n<p>Para amadurecer a resposta, vejamos as situa\u00e7\u00f5es de todos subconjuntos com mais de nove elementos:<\/p>\n<p style=\"text-align:center\"> [tex]S_{10}=\\{ \\, \\underline{\\textcolor{#6cda00}{1}} \\, , \\, \\underline{\\textcolor{#6cda00}{4} } \\, , \\, \\underline{\\textcolor{#6cda00}{6}} \\, , \\, \\underline{\\textcolor{#6cda00}{8} } \\, , \\, \\underline{\\textcolor{#6cda00}{9}} \\, , \\, \\underline{\\textcolor{#6cda00}{10}} \\, , \\, \\underline{\\textcolor{#6cda00}{12}} \\, , \\, \\underline{\\textcolor{#6cda00}{14}} \\, , \\, \\underline{\\textcolor{#6cda00}{15}} \\, , \\, \\underline{\\textcolor{#800000}{p_1}} \\, \\}[\/tex]<\/p>\n<p style=\"text-align:center\"> [tex]S_{11}=\\{ \\, \\underline{\\textcolor{#6cda00}{1}} \\, , \\, \\underline{\\textcolor{#6cda00}{4} } \\, , \\, \\underline{\\textcolor{#6cda00}{6}} \\, , \\, \\underline{\\textcolor{#6cda00}{8} } \\, , \\, \\underline{\\textcolor{#6cda00}{12}} \\, , \\, \\underline{\\textcolor{#6cda00}{10}} \\, , \\, \\underline{\\textcolor{#6cda00}{12}} \\, , \\, \\underline{\\textcolor{#6cda00}{14}} \\, , \\, \\underline{\\textcolor{#6cda00}{15}} \\, , \\, \\underline{\\textcolor{#800000}{p_1}} \\, , \\, \\underline{\\textcolor{#800000}{p_2}} \\, \\}[\/tex]<\/p>\n<p style=\"text-align:center\"> [tex]S_{12}=\\{ \\, \\underline{\\textcolor{#6cda00}{1}} \\, , \\, \\underline{\\textcolor{#6cda00}{4} } \\, , \\, \\underline{\\textcolor{#6cda00}{6}} \\, , \\, \\underline{\\textcolor{#6cda00}{8} } \\, , \\, \\underline{\\textcolor{#6cda00}{9}} \\, , \\, \\underline{\\textcolor{#6cda00}{10}} \\, , \\, \\underline{\\textcolor{#6cda00}{12}} \\, , \\, \\underline{\\textcolor{#6cda00}{14}} \\, , \\, \\underline{\\textcolor{#6cda00}{15}} \\, , \\, \\underline{\\textcolor{#800000}{p_1}} \\, , \\, \\underline{\\textcolor{#800000}{p_2}} \\, , \\, \\underline{\\textcolor{#800000}{p_3}} \\, \\}[\/tex]<\/p>\n<p style=\"text-align:center\"> [tex]S_{13}=\\{ \\, \\underline{\\textcolor{#6cda00}{1}} \\, , \\, \\underline{\\textcolor{#6cda00}{4} } \\, , \\, \\underline{\\textcolor{#6cda00}{6}} \\, , \\, \\underline{\\textcolor{#6cda00}{8} } \\, , \\, \\underline{\\textcolor{#6cda00}{9}} \\, , \\, \\underline{\\textcolor{#6cda00}{10}} \\, , \\, \\underline{\\textcolor{#6cda00}{12}} \\, , \\, \\underline{\\textcolor{#6cda00}{14}} \\, , \\, \\underline{\\textcolor{#6cda00}{15}} \\, , \\, \\underline{\\textcolor{#800000}{p_1}} \\, , \\, \\underline{\\textcolor{#800000}{p_2}} \\, , \\, \\underline{\\textcolor{#800000}{p_3}} \\, , \\, \\underline{\\textcolor{#800000}{p_4}} \\, \\}[\/tex]<\/p>\n<p style=\"text-align:center\"> [tex]S_{14}=\\{ \\, \\underline{\\textcolor{#6cda00}{1}} \\, , \\, \\underline{\\textcolor{#6cda00}{4} } \\, , \\, \\underline{\\textcolor{#6cda00}{6}} \\, , \\, \\underline{\\textcolor{#6cda00}{8} } \\, , \\, \\underline{\\textcolor{#6cda00}{9}} \\, , \\, \\underline{\\textcolor{#6cda00}{10}} \\, , \\, \\underline{\\textcolor{#6cda00}{12}} \\, , \\, \\underline{\\textcolor{#6cda00}{14}} \\, , \\, \\underline{\\textcolor{#6cda00}{15}} \\, , \\, \\underline{\\textcolor{#800000}{p_1}} \\, , \\, \\underline{\\textcolor{#800000}{p_2}} \\, , \\, \\underline{\\textcolor{#800000}{p_3}} \\, , \\, \\underline{\\textcolor{#800000}{p_4}} \\, , \\, \\underline{\\textcolor{#800000}{p_5}} \\, \\}[\/tex]<\/p>\n<p style=\"text-align:center\"> [tex]S_{15}=\\{ \\, \\underline{\\textcolor{#6cda00}{1}} \\, , \\, \\underline{\\textcolor{#6cda00}{4} } \\, , \\, \\underline{\\textcolor{#6cda00}{6}} \\, , \\, \\underline{\\textcolor{#6cda00}{8} } \\, , \\, \\underline{\\textcolor{#6cda00}{9}} \\, , \\, \\underline{\\textcolor{#6cda00}{10}} \\, , \\, \\underline{\\textcolor{#6cda00}{12}} \\, , \\, \\underline{\\textcolor{#6cda00}{14}} \\, , \\, \\underline{\\textcolor{#6cda00}{15}} \\, , \\, \\underline{\\textcolor{#800000}{p_1}} \\, , \\, \\underline{\\textcolor{#800000}{p_2}} \\, , \\, \\underline{\\textcolor{#800000}{p_3}} \\, , \\, \\underline{\\textcolor{#800000}{p_4}} \\, , \\, \\underline{\\textcolor{#800000}{p_5}} \\, , \\, \\underline{\\textcolor{#800000}{p_6}} \\, \\}[\/tex]<\/p>\n<p>onde [tex]\\textcolor{#800000}{p_1}, \\textcolor{#800000}{p_2}, \\textcolor{#800000}{p_3}, \\textcolor{#800000}{p_4}, \\textcolor{#800000}{p_5}, \\textcolor{#800000}{p_6} \\in \\{  \\, 2, \\, 3, \\, 5, \\, 7, \\, 11, \\, 13 \\, \\} \\, .[\/tex]<\/p>\n<p>Ent\u00e3o, o menor inteiro positivo [tex]m[\/tex] tal que qualquer subconjunto de [tex]A[\/tex] com [tex]m[\/tex] elementos tenha, pelo menos, um n\u00famero primo \u00e9 [tex] \\, \\fcolorbox{black}{#eee0e5}{$m=10$} \\, .[\/tex]<\/p>\n<hr style=\"height:1px; width:100%;background-color:#800000; margin-top: 10px; margin-bottom: 15px;border: 0 none\"\/>\n<p class=\"g2\" style=\"line-height:20px;\">Solu\u00e7\u00e3o elaborada pelos <strong>Moderadores do Blog<\/strong>.<\/p>\n<\/div>\n<p style=\"margin:20px\">\n<table style=\" height:auto; margin-left: auto; margin-right: auto;width:640px;\">\n<tr>\n<td class=\"bf\"><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-1001 alignright\" style=\"border: 0px;\" alt=\"\" src=\"http:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2013\/01\/menino.jpg\" width=\"80\" height=\"115\" \/><\/td>\n<td class=\"bf\">\n<p class=\"fala\" style=\"width:520px;background-color: #FFF5EE; padding:10px; font-family: calibri; font-size: 13px;color: #1C1C1C; line-height: 20px; \"> Se for conveniente, voc\u00ea pode obter um arquivo PDF desta p\u00e1gina, com o problema e a solu\u00e7\u00e3o, clicando no bot\u00e3o abaixo.<br \/>\nVoc\u00ea pode abrir o arquivo diretamente no seu navegador (<em>Chrome<\/em>, <em>Edge<\/em>, <em>Firefox<\/em>, <em>Safari<\/em>, entre outros), mas tamb\u00e9m pode utilizar o software gratuito <em><strong>Adobe Acrobat Reader<\/strong><\/em>.<br \/>\nCaso o dispositivo que voc\u00ea est\u00e1 utilizando n\u00e3o tenha o <strong><em>Acrobat Reader<\/em><\/strong> instalado, \u00e9 s\u00f3 clicar <a href=\"http:\/\/get.adobe.com\/br\/reader\/\" rel=\"noopener\" target=\"_blank\"><strong>AQUI<\/strong><\/a> para fazer o download adequado ao seu dispositivo.<\/p>\n<\/td>\n<\/tr>\n<\/table>\n<div style=\" float:right;  width: 100px;\">\n<p style=\"text-align: center; border-style: dotted; border-color :#FFFAFA; border-width :thin; width:90px;  height:40px;  padding: 5px; background-color: #800000;\">\n<a href=\"http:\/\/clubes.obmep.org.br\/blog\/wp-content\/uploads\/2019\/12\/N\u00fameros-primos-em-um-conjunto.pdf\" title=\" Arquivo PDF\" download=\"Clubes_ N\u00fameros primos em um conjunto.pdf\"><span style=\"color: #FFFAFA; font-family: georgia; font-size: 16px;\"><strong>Arquivo <\/strong><\/span><\/a>\n <\/p>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>&#9999; Link do problema para dispositivos da Apple. Problema (A partir do 8\u00ba ano do E. F. &#8211; N\u00edvel de dificuldade: M\u00e9dio) Seja [tex]A=\\{1, \\, 2, \\, 3, \\, 4, \\, 5, \\, 6, \\, 7, \\, 8, \\, 9, \\, 10, \\, 11, \\, 12, \\, 13, \\, 14, \\, 15 \\} \\, .[\/tex] &hellip; <\/p>\n<p><a class=\"more-link btn\" href=\"https:\/\/clubes.obmep.org.br\/blog\/problema-para-ajudar-na-escola-numeros-primos-em-um-conjunto\/\">Continue lendo<\/a><\/p>\n","protected":false},"author":2,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"template-onecolumn.php","meta":{"footnotes":""},"class_list":["post-107486","page","type-page","status-publish","hentry","nodate","item-wrap"],"_links":{"self":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages\/107486","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/comments?post=107486"}],"version-history":[{"count":86,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages\/107486\/revisions"}],"predecessor-version":[{"id":219643,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages\/107486\/revisions\/219643"}],"wp:attachment":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/media?parent=107486"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}