{"id":104494,"date":"2018-06-19T21:17:44","date_gmt":"2018-06-20T00:17:44","guid":{"rendered":"http:\/\/clubes.obmep.org.br\/blog\/?page_id=104494"},"modified":"2023-04-30T02:59:19","modified_gmt":"2023-04-30T05:59:19","slug":"problema-polinomio-de-segundo-grau","status":"publish","type":"page","link":"https:\/\/clubes.obmep.org.br\/blog\/problema-polinomio-de-segundo-grau\/","title":{"rendered":".Problema: Polin\u00f4mio de segundo grau"},"content":{"rendered":"<p style=\"margin:10px\">\n<div class=\"g1n\" style=\"line-height:28px;\">\n<p class=\"tit\" style=\"line-height:25px;margin:10px\">Problema<br \/>\n<span style=\"font-size:12px;color:#800000\"> (Indicado a partir do 8\u00ba ano do E. F.)<\/span><\/p>\n<hr style=\"height:1px; width:100%;background-color:#800000; margin-top: 10px; margin-bottom: 20px;border: 0 none\"\/>\nSe [tex]x[\/tex] \u00e9 um n\u00famero real que satisfaz a igualdade  [tex]x^3=x+2[\/tex], encontre um polin\u00f4mio do segundo grau que representa [tex]x^{10}[\/tex].<\/p>\n<p style=\"margin:10px\">\n<\/div>\n<p style=\"margin:30px\">\n<div class=\"g1n\" style=\"line-height:27px;\">\n<p class=\"tit\" style=\"line-height:30px;margin:10px\">Solu\u00e7\u00e3o <\/p>\n<hr style=\"height:1px; width:100%;background-color:#800000; margin-top: 10px; margin-bottom: 30px;border: 0 none\"\/>\n<ul>\n<li>Inicialmente, observe que<br \/>\n[tex]\\qquad \\begin{align*} \\boxed{x^{10}}&#038;=(x^3)^3\\cdot x\\\\<br \/>\n&#038; =(x+2)^3\\cdot x\\\\<br \/>\n&#038;=(x^3+6x^2+12x+8)\\cdot x.\\qquad \\textcolor{#800000}{(i)}\\end{align*}[\/tex]<\/li>\n<li>Agora, substituindo [tex]x^3[\/tex] por [tex]x+2[\/tex] na express\u00e3o [tex] \\textcolor{#800000}{(i)}[\/tex], vem:<br \/>\n[tex]\\qquad \\begin{align*} (x^3+6x^2+12x+8)\\cdot x&#038;= (x+2+6x^2+12x+8)\\cdot x\\\\<br \/>\n&#038;=(6x^2+13x+10)\\cdot x\\\\<br \/>\n&#038;=6x^3+13x^2+10x \\, .\\qquad \\textcolor{#800000}{(ii)}\\end{align*}[\/tex]<\/li>\n<li>Mais uma vez, substituindo [tex]x^3[\/tex] por [tex]x+2 \\, [\/tex], agora em [tex] \\textcolor{#800000}{(ii)}[\/tex], temos:<br \/>\n[tex]\\qquad \\begin{align*} 6x^3+13x^2+10x&#038;=6(x+2)+13x^2+10x\\\\<br \/>\n&#038;=\\boxed{13x^2+16x+12}.\\end{align*}[\/tex]<\/li>\n<\/ul>\n<p>Assim, se  [tex]x^3=x+2[\/tex], ent\u00e3o [tex]\\boxed{x^{10}=13x^2+16x+12} \\, [\/tex] e, portanto, o polin\u00f4mio [tex] \\, \\fcolorbox{black}{#eee0e5}{$p(t)=13t^2+16t+12$}[\/tex] \u00e9 tal que [tex]p(x)=x^{10} \\, .[\/tex]<\/p>\n<hr style=\"height:1px; width:100%;background-color:#800000; margin-top: 10px; margin-bottom: 15px;border: 0 none\"\/>\n<p class=\"g2\" style=\"line-height:20px;\">Solu\u00e7\u00e3o elaborada pelos <strong>Moderadores do Blog<\/strong>.<\/p>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>Problema (Indicado a partir do 8\u00ba ano do E. F.) Se [tex]x[\/tex] \u00e9 um n\u00famero real que satisfaz a igualdade [tex]x^3=x+2[\/tex], encontre um polin\u00f4mio do segundo grau que representa [tex]x^{10}[\/tex]. Solu\u00e7\u00e3o Inicialmente, observe que [tex]\\qquad \\begin{align*} \\boxed{x^{10}}&#038;=(x^3)^3\\cdot x\\\\ &#038; =(x+2)^3\\cdot x\\\\ &#038;=(x^3+6x^2+12x+8)\\cdot x.\\qquad \\textcolor{#800000}{(i)}\\end{align*}[\/tex] Agora, substituindo [tex]x^3[\/tex] por [tex]x+2[\/tex] na express\u00e3o [tex] \\textcolor{#800000}{(i)}[\/tex], vem: [tex]\\qquad &hellip; <\/p>\n<p><a class=\"more-link btn\" href=\"https:\/\/clubes.obmep.org.br\/blog\/problema-polinomio-de-segundo-grau\/\">Continue lendo<\/a><\/p>\n","protected":false},"author":164,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"template-onecolumn.php","meta":{"footnotes":""},"class_list":["post-104494","page","type-page","status-publish","hentry","nodate","item-wrap"],"_links":{"self":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages\/104494","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/users\/164"}],"replies":[{"embeddable":true,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/comments?post=104494"}],"version-history":[{"count":28,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages\/104494\/revisions"}],"predecessor-version":[{"id":188425,"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/pages\/104494\/revisions\/188425"}],"wp:attachment":[{"href":"https:\/\/clubes.obmep.org.br\/blog\/wp-json\/wp\/v2\/media?parent=104494"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}